What is -3(-2)^2+2(-2)+2 ?

The solution to -3(-2)^2+2(-2)+2 is -14

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-3(-2)^2+2(-2)+2

- 3 (- 2)^{2} + 2 (- 2) + 2

- 14

Solution steps

- 3 (- 2)^{2} + 2 (- 2) + 2

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 3 \cdot 4 + 2 (- 2) + 2

Multiply and divide (left to right)

- 3 \cdot 4 : - 12

- 3 \cdot 4

- 3 \cdot 4 = - 12

= - 12

= - 12 + 2 (- 2) + 2

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= - 12 - 4 + 2

Add and subtract (left to right)

- 12 - 4 + 2 : - 14

- 12 - 4 + 2

- 12 - 4 = - 16

= - 16 + 2

- 16 + 2 = - 14

= - 14

= - 14

- 1^{3} - 5

(7 + 3)^{0}

- 1^{3} + 8

- 1^{3} + 5

4 (8 + 3 \times 5) - (- 9 + 7)