What is 3{20-[6^2-3(10-4)]} ?

The solution to 3{20-[6^2-3(10-4)]} is 6

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3{20-[6^2-3(10-4)]}

3 {20 - [6^{2} - 3 (10 - 4)]}

6

Solution steps

3 {20 - [6^{2} - 3 (10 - 4)]}

Follow the PEMDAS order of operations

Calculate within parentheses

{20 - [6^{2} - 3 (10 - 4)]} : 2

= 3 \cdot 2

Multiply and divide (left to right)

3 \cdot 2 : 6

= 6

8 - 6 \div (4 - 2)

(\frac{12}{3})^{3} \div 2^{5}

9 \times 5 + 2

- 5 + 8 - (12 + 9 - 3) + 1

(- 1) + (5) + (2) - (- 12)