What is 2(4(7+4(5*3-9))-3(40-8)) ?

The solution to 2(4(7+4(5*3-9))-3(40-8)) is 56

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2(4(7+4(5*3-9))-3(40-8))

2 (4 (7 + 4 (5 \cdot 3 - 9)) - 3 (40 - 8))

56

Solution steps

2 (4 (7 + 4 (5 \cdot 3 - 9)) - 3 (40 - 8))

Follow the PEMDAS order of operations

Calculate within parentheses

(4 (7 + 4 (5 \cdot 3 - 9)) - 3 (40 - 8)) : 28

4 (7 + 4 (5 \cdot 3 - 9)) - 3 (40 - 8)

Calculate within parentheses

(7 + 4 (5 \cdot 3 - 9)) : 31

7 + 4 (5 \cdot 3 - 9)

Calculate within parentheses

(5 \cdot 3 - 9) : 6

5 \cdot 3 - 9

Multiply and divide (left to right)

5 \cdot 3 : 15

5 \cdot 3

5 \cdot 3 = 15

= 15

= 15 - 9

Add and subtract (left to right)

15 - 9 : 6

15 - 9

15 - 9 = 6

= 6

= 6

= 7 + 4 \cdot 6

Multiply and divide (left to right)

4 \cdot 6 : 24

4 \cdot 6

4 \cdot 6 = 24

= 24

= 7 + 24

Add and subtract (left to right)

7 + 24 : 31

7 + 24

7 + 24 = 31

= 31

= 31

= 4 \cdot 31 - 3 (40 - 8)

Calculate within parentheses

(40 - 8) : 32

40 - 8

40 - 8 = 32

= 32

= 4 \cdot 31 - 3 \cdot 32

Multiply and divide (left to right)

4 \cdot 31 : 124

4 \cdot 31

4 \cdot 31 = 124

= 124

= 124 - 3 \cdot 32

Multiply and divide (left to right)

3 \cdot 32 : 96

3 \cdot 32

3 \cdot 32 = 96

= 96

= 124 - 96

Add and subtract (left to right)

124 - 96 : 28

124 - 96

124 - 96 = 28

= 28

= 28

= 2 \cdot 28

Multiply and divide (left to right)

2 \cdot 28 : 56

2 \cdot 28

2 \cdot 28 = 56

= 56

= 56

4^{2} + 6^{2}

\frac{250}{2}

\frac{28}{32}

532 + 2 (4^{3} - 4^{2})^{2}

\frac{20}{25}

What is 2(4(7+4(5*3-9))-3(40-8)) ?
The solution to 2(4(7+4(5*3-9))-3(40-8)) is 56