What is [6\times (4-6\div 2)]-[2-(1-10)\div 3] ?

The solution to [6\times (4-6\div 2)]-[2-(1-10)\div 3] is 1

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[6\times (4-6\div 2)]-[2-(1-10)\div 3]

[6 \times (4 - 6 \div 2)] - [2 - (1 - 10) \div 3]

1

Solution steps

[6 \times (4 - 6 \div 2)] - [2 - (1 - 10) \div 3]

Follow the PEMDAS order of operations

Calculate within parentheses

[6 \times (4 - 6 \div 2)] : 6

= 6 - [2 - (1 - 10) \div 3]

Calculate within parentheses

[2 - (1 - 10) \div 3] : 5

= 6 - 5

Add and subtract (left to right)

6 - 5 : 1

= 1

- 4^{2} + 5 \cdot (- 4) - 9

3 (1 - 2)^{2} - 7

2 (- 3)^{2} + 4 (- 3) + 1

3^{3} + (15 + 5) + (11 \times 2)

- 3 (2) + 5

What is [6\times (4-6\div 2)]-[2-(1-10)\div 3] ?
The solution to [6\times (4-6\div 2)]-[2-(1-10)\div 3] is 1