What is (7/7+2/7)-6/14 ?

The solution to (7/7+2/7)-6/14 is 6/7

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(7/7+2/7)-6/14

(\frac{7}{7} + \frac{2}{7}) - \frac{6}{14}

\frac{6}{7}

Solution steps

(\frac{7}{7} + \frac{2}{7}) - \frac{6}{14}

\frac{7}{7} = 1

Apply rule

\frac{a}{a} = 1

1

= 1 + \frac{2}{7} - \frac{6}{14}

\frac{6}{14} = \frac{3}{7}

Cancel the common factor:

2

\frac{3}{7}

= 1 + \frac{2}{7} - \frac{3}{7}

Follow the PEMDAS order of operations

Add and subtract (left to right)

1 + \frac{2}{7} - \frac{3}{7} : \frac{6}{7}

1 + \frac{2}{7} - \frac{3}{7}

1 + \frac{2}{7} = \frac{9}{7}

1 + \frac{2}{7}

Convert element to fraction:

1 = \frac{1 \cdot 7}{7}

= \frac{1 \cdot 7}{7} + \frac{2}{7}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1 \cdot 7 + 2}{7}

1 \cdot 7 + 2 = 9

1 \cdot 7 + 2

Multiply the numbers:

1 \cdot 7 = 7

= 7 + 2

Add the numbers:

7 + 2 = 9

= 9

= \frac{9}{7}

= \frac{9}{7} - \frac{3}{7}

\frac{9}{7} - \frac{3}{7} = \frac{6}{7}

\frac{9}{7} - \frac{3}{7}

Apply rule

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{9 - 3}{7}

Subtract the numbers:

9 - 3 = 6

= \frac{6}{7}

= \frac{6}{7}

= \frac{6}{7}

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