What is 12-[20-2((6^2)/3*2^2)] ?

The solution to 12-[20-2((6^2)/3*2^2)] is 88

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simplify 12-[20-2((6^2)/3*2^2)]

simplify

12 - [20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2})]

88

Solution steps

12 - (20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2}))

- (20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2})) = 76

- (20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2}))

20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2}) = - 76

20 - 2 (\frac{6 ^{2}}{3} \cdot 2^{2})

2 (\frac{6 ^{2}}{3} \cdot 2^{2}) = 96

2 (\frac{6 ^{2}}{3} \cdot 2^{2})

\frac{6 ^{2}}{3} \cdot 2^{2} = 48

\frac{6 ^{2}}{3} \cdot 2^{2}

2^{2} = 4

= \frac{6 ^{2}}{3} \cdot 4

Cancel

\frac{6 ^{2}}{3} : 12

\frac{6 ^{2}}{3}

6^{2} = 36

= \frac{36}{3}

Divide the numbers:

\frac{36}{3} = 12

= 12

= 12 \cdot 4

Multiply the numbers:

12 \cdot 4 = 48

= 48

= 2 \cdot 48

Multiply the numbers:

2 \cdot 48 = 96

= 96

= 20 - 96

Subtract the numbers:

20 - 96 = - 76

= - 76

= - (- 76)

Apply rule:

- (- a) = a

- (- 76) = 76

= 76

= 12 + 76

12 + 76 = 88

12 + 76

Line up the numbers

+ 1726

Add each column of digits, starting on the right and working left.

If the sum of a column is more than ten, 'carry' digits to the next column on the left.

Add the digits of the bolded column:

2 + 6 = 8

\frac{+ 1 7 2 6}{8}

Add the digits of the bolded column:

1 + 7 = 8

\frac{+ 1 7 2 6}{8 8}

88

= 88

4 (2)^{2}

2 (- 2)^{3}

5 \cdot 1 0^{3}

- 4 (2)^{2} + \frac{5 ^{3}}{5}

2^{2} + 2^{2}