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Beliebt Vorkalkül >

mittelpunkt (15,-3),(5,12)

Lösung

mittelpunkt

(15, - 3), (5, 12)

Lösung

(10, \frac{9}{2})

Schritte zur Lösung

Mittelpunkt von

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (15, - 3), (x_{2}, y_{2}) = (5, 12)

= (\frac{5 + 15}{2}, \frac{12 - 3}{2})

Fasse zusammen

= (10, \frac{9}{2})

Graph

Beliebte Beispiele

senkrecht y= 2/3 x-3,(0,-3)

p er p e n d i c u l a r y = \frac{2}{3} x - 3, (0, - 3)

polar (2sqrt(2),2sqrt(2))

p o l a r (22, 22)

tangent f(x)=ln(x),\at x=1

t an g e n t f (x) = ln (x), at x = 1

polar (4sqrt(3),4)

p o l a r (43, 4)

in t e g r a l x