sec(θ)=-sqrt(2)

Lösung

sec (θ) = - 2

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

Grad

θ = 13 5^{\circ} + 36 0^{\circ} n, θ = 22 5^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

sec (θ) = - 2

Allgemeine Lösung für

sec (θ) = - 2

sec (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sec (x) 1 \frac{2 3}{3} 22 Undefined - 2 - 2 - \frac{2 3}{3} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sec (x) - 1 - \frac{2 3}{3} - 2 - 2 Undefined 22 \frac{2 3}{3}

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

θ = \frac{3 π}{4} + 2 πn, θ = \frac{5 π}{4} + 2 πn

2 sin (θ) = - 3

tan (\frac{x}{2}) = - \frac{3}{3}

sec (3 x) - 2 = 0

cot (x) - 3 = 0

tan (x) = cot (x)