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人気のある三角関数 >

5-10sin^2(x)=0

解

5 - 10 sin^{2} (x) = 0

解

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

+1

度

x = 4 5^{\circ} + 36 0^{\circ} n, x = 13 5^{\circ} + 36 0^{\circ} n, x = 22 5^{\circ} + 36 0^{\circ} n, x = 31 5^{\circ} + 36 0^{\circ} n

解答ステップ

5 - 10 sin^{2} (x) = 0

置換で解く

5 - 10 sin^{2} (x) = 0

仮定:

sin (x) = u

5 - 10 u^{2} = 0

5 - 10 u^{2} = 0 : u = \frac{1}{2}, u = - \frac{1}{2}

5 - 10 u^{2} = 0

5

を右側に移動します

5 - 10 u^{2} = 0

両辺から

5

を引く

5 - 10 u^{2} - 5 = 0 - 5

簡素化

- 10 u^{2} = - 5

- 10 u^{2} = - 5

以下で両辺を割る

- 10

- 10 u^{2} = - 5

以下で両辺を割る

- 10

\frac{- 10 u ^{2}}{- 10} = \frac{- 5}{- 10}

簡素化

\frac{- 10 u ^{2}}{- 10} = \frac{- 5}{- 10}

簡素化

\frac{- 10 u ^{2}}{- 10} : u^{2}

\frac{- 10 u ^{2}}{- 10}

分数の規則を適用する:

\frac{- a}{- b} = \frac{a}{b}

= \frac{10 u ^{2}}{10}

数を割る:

\frac{10}{10} = 1

= u^{2}

簡素化

\frac{- 5}{- 10} : \frac{1}{2}

\frac{- 5}{- 10}

分数の規則を適用する:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5}{10}

共通因数を約分する:

5

= \frac{1}{2}

u^{2} = \frac{1}{2}

u^{2} = \frac{1}{2}

u^{2} = \frac{1}{2}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{1}{2}, u = - \frac{1}{2}

代用を戻す

u = sin (x)

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2} : x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = \frac{1}{2}

以下の一般解

sin (x) = \frac{1}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn

sin (x) = - \frac{1}{2} : x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

sin (x) = - \frac{1}{2}

以下の一般解

sin (x) = - \frac{1}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

すべての解を組み合わせる

x = \frac{π}{4} + 2 πn, x = \frac{3 π}{4} + 2 πn, x = \frac{5 π}{4} + 2 πn, x = \frac{7 π}{4} + 2 πn

グラフ

人気の例

sec^{2} (θ) - 2 = 0

2-sin^2(x)=2cos^2(x/2)

2 - sin^{2} (x) = 2 cos^{2} (\frac{x}{2})

sec(θ/5)=sqrt(10)

sec (\frac{θ}{5}) = 10

(sin(x))^4=((cos(x))^2)/2

(sin (x))^{4} = \frac{( cos ( x ) ) ^{2}}{2}

cos (θ) = \frac{15}{17}