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Popular Trigonometria >

3tanh(2θ)=5sech(θ)+1

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Solução

3tanh(2θ)=5sech(θ)+1

Solução

θ=ln(4.82043…)
+1
Graus
θ=90.11846…∘
Passos da solução
3tanh(2θ)=5sech(θ)+1
Reeecreva usando identidades trigonométricas
3tanh(2θ)=5sech(θ)+1
Use a identidade hiperbólica: tanh(x)=ex+e−xex−e−x​3⋅e2θ+e−2θe2θ−e−2θ​=5sech(θ)+1
Use a identidade hiperbólica: sech(x)=ex+e−x2​3⋅e2θ+e−2θe2θ−e−2θ​=5⋅eθ+e−θ2​+1
3⋅e2θ+e−2θe2θ−e−2θ​=5⋅eθ+e−θ2​+1
3⋅e2θ+e−2θe2θ−e−2θ​=5⋅eθ+e−θ2​+1:θ=ln(4.82043…)
3⋅e2θ+e−2θe2θ−e−2θ​=5⋅eθ+e−θ2​+1
Aplicar as propriedades dos expoentes
3⋅e2θ+e−2θe2θ−e−2θ​=5⋅eθ+e−θ2​+1
Aplicar as propriedades dos expoentes: abc=(ab)ce2θ=(eθ)2,e−2θ=(eθ)−2,e−θ=(eθ)−13⋅(eθ)2+(eθ)−2(eθ)2−(eθ)−2​=5⋅eθ+(eθ)−12​+1
3⋅(eθ)2+(eθ)−2(eθ)2−(eθ)−2​=5⋅eθ+(eθ)−12​+1
Reescrever a equação com eθ=u3⋅(u)2+(u)−2(u)2−(u)−2​=5⋅u+(u)−12​+1
Resolver 3⋅u2+u−2u2−u−2​=5⋅u+u−12​+1:u≈−0.45284…,u≈4.82043…
3⋅u2+u−2u2−u−2​=5⋅u+u−12​+1
Simplificaru4+13(u4−1)​=u2+110u​+1
Multiplicar pelo mínimo múltiplo comum
u4+13(u4−1)​=u2+110u​+1
Encontrar o mínimo múltiplo comum de u4+1,u2+1:(u2+1)(u2+2​u+1)(u2−2​u+1)
u4+1,u2+1
Mínimo múltiplo comum (MMC)
Fatorar as expressões
Fatorar u4+1:(u2+2​u+1)(u2−2​u+1)
u4+1
u4+1=(u2+2​u+1)(u2−2​u+1)=(u2+2​u+1)(u2−2​u+1)
Calcular uma expressão que seja composta por fatores que estejam presentes tanto em (u2+2​u+1)(u2−2​u+1) quanto em u2+1=(u2+1)(u2+2​u+1)(u2−2​u+1)
Multiplicar pelo mínimo múltiplo comum=(u2+1)(u2+2​u+1)(u2−2​u+1)u4+13(u4−1)​(u2+1)(u2+2​u+1)(u2−2​u+1)=u2+110u​(u2+1)(u2+2​u+1)(u2−2​u+1)+1⋅(u2+1)(u2+2​u+1)(u2−2​u+1)
Simplificar
u4+13(u4−1)​(u2+1)(u2+2​u+1)(u2−2​u+1)=u2+110u​(u2+1)(u2+2​u+1)(u2−2​u+1)+1⋅(u2+1)(u2+2​u+1)(u2−2​u+1)
Simplificar u4+13(u4−1)​(u2+1)(u2+2​u+1)(u2−2​u+1):3(u+1)(u−1)(u2+1)2
u4+13(u4−1)​(u2+1)(u2+2​u+1)(u2−2​u+1)
Multiplicar frações: a⋅cb​=ca⋅b​=u4+13(u4−1)(u2+1)(u2+2​u+1)(u2−2​u+1)​
Fatorar 3(u4−1)(u2+1)(u2+2​u+1)(u2−2​u+1):3(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)
3(u4−1)(u2+1)(u2+2​u+1)(u2−2​u+1)
Fatorar u4−1:(u2+1)(u+1)(u−1)
u4−1
Reescrever u4−1 como (u2)2−12
u4−1
Reescrever 1 como 12=u4−12
Aplicar as propriedades dos expoentes: abc=(ab)cu4=(u2)2=(u2)2−12
=(u2)2−12
Aplicar a regra da diferença de quadrados: x2−y2=(x+y)(x−y)(u2)2−12=(u2+1)(u2−1)=(u2+1)(u2−1)
Fatorar u2−1:(u+1)(u−1)
u2−1
Reescrever 1 como 12=u2−12
Aplicar a regra da diferença de quadrados: x2−y2=(x+y)(x−y)u2−12=(u+1)(u−1)=(u+1)(u−1)
=(u2+1)(u+1)(u−1)
=3(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)
=u4+13(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)​
u4+1=(u2+2​u+1)(u2−2​u+1)=(u2+2​u+1)(u2−2​u+1)3(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)​
Cancelar (u2+2​u+1)(u2−2​u+1)3(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)​:3(u+1)(u−1)(u2+1)2
(u2+2​u+1)(u2−2​u+1)3(u+1)(u−1)(u2+1)2(u2+2​u+1)(u2−2​u+1)​
Eliminar o fator comum: u2+2​u+1=u2−2​u+13(u+1)(u−1)(u2+1)2(u2−2​u+1)​
Eliminar o fator comum: u2−2​u+1=3(u+1)(u−1)(u2+1)2
=3(u+1)(u−1)(u2+1)2
Simplificar u2+110u​(u2+1)(u2+2​u+1)(u2−2​u+1):10u(u2+2​u+1)(u2−2​u+1)
u2+110u​(u2+1)(u2+2​u+1)(u2−2​u+1)
Multiplicar frações: a⋅cb​=ca⋅b​=u2+110u(u2+1)(u2+2​u+1)(u2−2​u+1)​
Eliminar o fator comum: u2+1=10u(u2+2​u+1)(u2−2​u+1)
Simplificar 1⋅(u2+1)(u2+2​u+1)(u2−2​u+1):(u2+1)(u2+2​u+1)(u2−2​u+1)
1⋅(u2+1)(u2+2​u+1)(u2−2​u+1)
Multiplicar: 1⋅(u2+1)=(u2+1)=(u2+1)(u2+2​u+1)(u2−2​u+1)
3(u+1)(u−1)(u2+1)2=10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1)
3(u+1)(u−1)(u2+1)2=10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1)
3(u+1)(u−1)(u2+1)2=10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1)
Resolver 3(u+1)(u−1)(u2+1)2=10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1):u≈−0.45284…,u≈4.82043…
3(u+1)(u−1)(u2+1)2=10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1)
Expandir 3(u+1)(u−1)(u2+1)2:3u6+3u4−3u2−3
3(u+1)(u−1)(u2+1)2
(u2+1)2=u4+2u2+1
(u2+1)2
Aplique a fórmula do quadrado perfeito: (a+b)2=a2+2ab+b2a=u2,b=1
=(u2)2+2u2⋅1+12
Simplificar (u2)2+2u2⋅1+12:u4+2u2+1
(u2)2+2u2⋅1+12
Aplicar a regra 1a=112=1=(u2)2+2⋅1⋅u2+1
(u2)2=u4
(u2)2
Aplicar as propriedades dos expoentes: (ab)c=abc=u2⋅2
Multiplicar os números: 2⋅2=4=u4
2u2⋅1=2u2
2u2⋅1
Multiplicar os números: 2⋅1=2=2u2
=u4+2u2+1
=u4+2u2+1
=3(u+1)(u−1)(u4+2u2+1)
Expandir (u+1)(u−1):u2−1
(u+1)(u−1)
Aplicar a regra da diferença de quadrados: (a+b)(a−b)=a2−b2a=u,b=1=u2−12
Aplicar a regra 1a=112=1=u2−1
=3(u2−1)(u4+2u2+1)
Expandir (u2−1)(u4+2u2+1):u6+u4−u2−1
(u2−1)(u4+2u2+1)
Aplicar a seguinte regra dos produtos notáveis=u2u4+u2⋅2u2+u2⋅1+(−1)u4+(−1)⋅2u2+(−1)⋅1
Aplicar as regras dos sinais+(−a)=−a=u4u2+2u2u2+1⋅u2−1⋅u4−1⋅2u2−1⋅1
Simplificar u4u2+2u2u2+1⋅u2−1⋅u4−1⋅2u2−1⋅1:u6+u4−u2−1
u4u2+2u2u2+1⋅u2−1⋅u4−1⋅2u2−1⋅1
u4u2=u6
u4u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu4u2=u4+2=u4+2
Somar: 4+2=6=u6
2u2u2=2u4
2u2u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u2=u2+2=2u2+2
Somar: 2+2=4=2u4
1⋅u2=u2
1⋅u2
Multiplicar: 1⋅u2=u2=u2
1⋅u4=u4
1⋅u4
Multiplicar: 1⋅u4=u4=u4
1⋅2u2=2u2
1⋅2u2
Multiplicar os números: 1⋅2=2=2u2
1⋅1=1
1⋅1
Multiplicar os números: 1⋅1=1=1
=u6+2u4+u2−u4−2u2−1
Agrupar termos semelhantes=u6+2u4−u4+u2−2u2−1
Somar elementos similares: u2−2u2=−u2=u6+2u4−u4−u2−1
Somar elementos similares: 2u4−u4=u4=u6+u4−u2−1
=u6+u4−u2−1
=3(u6+u4−u2−1)
Expandir 3(u6+u4−u2−1):3u6+3u4−3u2−3
3(u6+u4−u2−1)
Aplicar a seguinte regra dos produtos notáveis=3u6+3u4+3(−u2)+3(−1)
Aplicar as regras dos sinais+(−a)=−a=3u6+3u4−3u2−3⋅1
Multiplicar os números: 3⋅1=3=3u6+3u4−3u2−3
=3u6+3u4−3u2−3
Expandir 10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1):10u5+10u+u6+u4+u2+1
10u(u2+2​u+1)(u2−2​u+1)+(u2+1)(u2+2​u+1)(u2−2​u+1)
Expandir 10u(u2+2​u+1)(u2−2​u+1):10u5+10u
Expandir (u2+2​u+1)(u2−2​u+1):u4+1
(u2+2​u+1)(u2−2​u+1)
Aplicar a seguinte regra dos produtos notáveis=u2u2+u2(−2​u)+u2⋅1+2​uu2+2​u(−2​u)+2​u⋅1+1⋅u2+1⋅(−2​u)+1⋅1
Aplicar as regras dos sinais+(−a)=−a=u2u2−2​u2u+1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1
Simplificar u2u2−2​u2u+1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1:u4+1
u2u2−2​u2u+1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1
Agrupar termos semelhantes=u2u2−2​u2u+1⋅u2+2​u2u+1⋅u2−2​2​uu+1⋅2​u−1⋅2​u+1⋅1
Somar elementos similares: 1⋅2​u−1⋅2​u=0=u2u2−2​u2u+1⋅u2+2​u2u+1⋅u2−2​2​uu+1⋅1
Somar elementos similares: −2​u2u+2​u2u=0=u2u2+1⋅u2+1⋅u2−2​2​uu+1⋅1
Somar elementos similares: 1⋅u2+1⋅u2=2u2=u2u2+2u2−2​2​uu+1⋅1
u2u2=u4
u2u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u2=u2+2=u2+2
Somar: 2+2=4=u4
2​2​uu=2u2
2​2​uu
Aplicar as propriedades dos radicais: a​a​=a2​2​=2=2uu
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cuu=u1+1=2u1+1
Somar: 1+1=2=2u2
1⋅1=1
1⋅1
Multiplicar os números: 1⋅1=1=1
=u4+2u2−2u2+1
Somar elementos similares: 2u2−2u2=0=u4+1
=u4+1
=10u(u4+1)
Expandir 10u(u4+1):10u5+10u
10u(u4+1)
Colocar os parênteses utilizando: a(b+c)=ab+aca=10u,b=u4,c=1=10uu4+10u⋅1
=10u4u+10⋅1⋅u
Simplificar 10u4u+10⋅1⋅u:10u5+10u
10u4u+10⋅1⋅u
10u4u=10u5
10u4u
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu4u=u4+1=10u4+1
Somar: 4+1=5=10u5
10⋅1⋅u=10u
10⋅1⋅u
Multiplicar os números: 10⋅1=10=10u
=10u5+10u
=10u5+10u
=10u5+10u
=10u5+10u+(u2+1)(u2+2​u+1)(u2−2​u+1)
Expandir (u2+1)(u2+2​u+1)(u2−2​u+1):u6+u4+u2+1
Expandir (u2+1)(u2+2​u+1):u4+2​u3+2u2+2​u+1
(u2+1)(u2+2​u+1)
Aplicar a seguinte regra dos produtos notáveis=u2u2+u22​u+u2⋅1+1⋅u2+1⋅2​u+1⋅1
=u2u2+2​u2u+1⋅u2+1⋅u2+1⋅2​u+1⋅1
Simplificar u2u2+2​u2u+1⋅u2+1⋅u2+1⋅2​u+1⋅1:u4+2​u3+2u2+2​u+1
u2u2+2​u2u+1⋅u2+1⋅u2+1⋅2​u+1⋅1
Somar elementos similares: 1⋅u2+1⋅u2=2u2=u2u2+2​u2u+2u2+1⋅2​u+1⋅1
u2u2=u4
u2u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u2=u2+2=u2+2
Somar: 2+2=4=u4
2​u2u=2​u3
2​u2u
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u=u2+1=2​u2+1
Somar: 2+1=3=2​u3
1⋅2​u=2​u
1⋅2​u
Multiplicar: 1⋅2​=2​=2​u
1⋅1=1
1⋅1
Multiplicar os números: 1⋅1=1=1
=u4+2​u3+2u2+2​u+1
=u4+2​u3+2u2+2​u+1
=(u4+2​u3+2u2+2​u+1)(u2−2​u+1)
Expandir (u4+2​u3+2u2+2​u+1)(u2−2​u+1):u6+u4+u2+1
(u4+2​u3+2u2+2​u+1)(u2−2​u+1)
Aplicar a seguinte regra dos produtos notáveis=u4u2+u4(−2​u)+u4⋅1+2​u3u2+2​u3(−2​u)+2​u3⋅1+2u2u2+2u2(−2​u)+2u2⋅1+2​uu2+2​u(−2​u)+2​u⋅1+1⋅u2+1⋅(−2​u)+1⋅1
Aplicar as regras dos sinais+(−a)=−a=u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−22​u2u+2⋅1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1
Simplificar u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−22​u2u+2⋅1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1:u6+u4+u2+1
u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−22​u2u+2⋅1⋅u2+2​u2u−2​2​uu+1⋅2​u+1⋅u2−1⋅2​u+1⋅1
Agrupar termos semelhantes=u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−22​u2u+2⋅1⋅u2+2​u2u+1⋅u2−2​2​uu+1⋅2​u−1⋅2​u+1⋅1
Somar elementos similares: 1⋅2​u−1⋅2​u=0=u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−22​u2u+2⋅1⋅u2+2​u2u+1⋅u2−2​2​uu+1⋅1
Somar elementos similares: −22​u2u+2​u2u=−2​u2u=u4u2−2​u4u+1⋅u4+2​u3u2−2​2​u3u+1⋅2​u3+2u2u2−2​u2u+2⋅1⋅u2+1⋅u2−2​2​uu+1⋅1
u4u2=u6
u4u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu4u2=u4+2=u4+2
Somar: 4+2=6=u6
2​u4u=2​u5
2​u4u
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu4u=u4+1=2​u4+1
Somar: 4+1=5=2​u5
1⋅u4=u4
1⋅u4
Multiplicar: 1⋅u4=u4=u4
2​u3u2=2​u5
2​u3u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu3u2=u3+2=2​u3+2
Somar: 3+2=5=2​u5
2​2​u3u=2u4
2​2​u3u
Aplicar as propriedades dos radicais: a​a​=a2​2​=2=2u3u
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu3u=u3+1=2u3+1
Somar: 3+1=4=2u4
1⋅2​u3=2​u3
1⋅2​u3
Multiplicar: 1⋅2​=2​=2​u3
2u2u2=2u4
2u2u2
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u2=u2+2=2u2+2
Somar: 2+2=4=2u4
2​u2u=2​u3
2​u2u
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cu2u=u2+1=2​u2+1
Somar: 2+1=3=2​u3
2⋅1⋅u2=2u2
2⋅1⋅u2
Multiplicar os números: 2⋅1=2=2u2
1⋅u2=u2
1⋅u2
Multiplicar: 1⋅u2=u2=u2
2​2​uu=2u2
2​2​uu
Aplicar as propriedades dos radicais: a​a​=a2​2​=2=2uu
Aplicar as propriedades dos expoentes: ab⋅ac=ab+cuu=u1+1=2u1+1
Somar: 1+1=2=2u2
1⋅1=1
1⋅1
Multiplicar os números: 1⋅1=1=1
=u6−2​u5+u4+2​u5−2u4+2​u3+2u4−2​u3+2u2+u2−2u2+1
Agrupar termos semelhantes=u6−2​u5+2​u5+u4−2u4+2u4+2​u3−2​u3+2u2+u2−2u2+1
Somar elementos similares: 2​u3−2​u3=0=u6−2​u5+2​u5+u4−2u4+2u4+2u2+u2−2u2+1
Somar elementos similares: −2​u5+2​u5=0=u6+u4−2u4+2u4+2u2+u2−2u2+1
Somar elementos similares: 2u2+u2−2u2=u2=u6+u4−2u4+2u4+u2+1
Somar elementos similares: u4−2u4+2u4=u4=u6+u4+u2+1
=u6+u4+u2+1
=u6+u4+u2+1
=10u5+10u+u6+u4+u2+1
3u6+3u4−3u2−3=10u5+10u+u6+u4+u2+1
Trocar lados10u5+10u+u6+u4+u2+1=3u6+3u4−3u2−3
Subtrair 3u6+3u4−3u2−3 de ambos os lados10u5+10u+u6+u4+u2+1−(3u6+3u4−3u2−3)=3u6+3u4−3u2−3−(3u6+3u4−3u2−3)
Simplificar
10u5+10u+u6+u4+u2+1−(3u6+3u4−3u2−3)=3u6+3u4−3u2−3−(3u6+3u4−3u2−3)
Simplificar 10u5+10u+u6+u4+u2+1−(3u6+3u4−3u2−3):−2u6+10u5−2u4+4u2+10u+4
10u5+10u+u6+u4+u2+1−(3u6+3u4−3u2−3)
−(3u6+3u4−3u2−3):−3u6−3u4+3u2+3
−(3u6+3u4−3u2−3)
Colocar os parênteses=−(3u6)−(3u4)−(−3u2)−(−3)
Aplicar as regras dos sinais−(−a)=a,−(a)=−a=−3u6−3u4+3u2+3
=10u5+10u+u6+u4+u2+1−3u6−3u4+3u2+3
Simplificar 10u5+10u+u6+u4+u2+1−3u6−3u4+3u2+3:−2u6+10u5−2u4+4u2+10u+4
10u5+10u+u6+u4+u2+1−3u6−3u4+3u2+3
Agrupar termos semelhantes=u6−3u6+10u5+u4−3u4+u2+3u2+10u+1+3
Somar elementos similares: u2+3u2=4u2=u6−3u6+10u5+u4−3u4+4u2+10u+1+3
Somar elementos similares: u4−3u4=−2u4=u6−3u6+10u5−2u4+4u2+10u+1+3
Somar elementos similares: u6−3u6=−2u6=−2u6+10u5−2u4+4u2+10u+1+3
Somar: 1+3=4=−2u6+10u5−2u4+4u2+10u+4
=−2u6+10u5−2u4+4u2+10u+4
Simplificar 3u6+3u4−3u2−3−(3u6+3u4−3u2−3):0
3u6+3u4−3u2−3−(3u6+3u4−3u2−3)
Somar elementos similares: 3u6+3u4−3u2−3−(3u6+3u4−3u2−3)=0
=0
−2u6+10u5−2u4+4u2+10u+4=0
−2u6+10u5−2u4+4u2+10u+4=0
Encontrar uma solução para −2u6+10u5−2u4+4u2+10u+4=0 utilizando o método de Newton-Raphson:u≈−0.45284…
−2u6+10u5−2u4+4u2+10u+4=0
Definição de método de Newton-Raphson
f(u)=−2u6+10u5−2u4+4u2+10u+4
Encontrar f′(u):−12u5+50u4−8u3+8u+10
dud​(−2u6+10u5−2u4+4u2+10u+4)
Aplicar a regra da soma/diferença: (f±g)′=f′±g′=−dud​(2u6)+dud​(10u5)−dud​(2u4)+dud​(4u2)+dud​(10u)+dud​(4)
dud​(2u6)=12u5
dud​(2u6)
Retirar a constante: (a⋅f)′=a⋅f′=2dud​(u6)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=2⋅6u6−1
Simplificar=12u5
dud​(10u5)=50u4
dud​(10u5)
Retirar a constante: (a⋅f)′=a⋅f′=10dud​(u5)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=10⋅5u5−1
Simplificar=50u4
dud​(2u4)=8u3
dud​(2u4)
Retirar a constante: (a⋅f)′=a⋅f′=2dud​(u4)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=2⋅4u4−1
Simplificar=8u3
dud​(4u2)=8u
dud​(4u2)
Retirar a constante: (a⋅f)′=a⋅f′=4dud​(u2)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=4⋅2u2−1
Simplificar=8u
dud​(10u)=10
dud​(10u)
Retirar a constante: (a⋅f)′=a⋅f′=10dudu​
Aplicar a regra da derivação: dudu​=1=10⋅1
Simplificar=10
dud​(4)=0
dud​(4)
Derivada de uma constante: dxd​(a)=0=0
=−12u5+50u4−8u3+8u+10+0
Simplificar=−12u5+50u4−8u3+8u+10
Seja u0​=0Calcular un+1​ até que Δun+1​<0.000001
u1​=−0.4:Δu1​=0.4
f(u0​)=−2⋅06+10⋅05−2⋅04+4⋅02+10⋅0+4=4f′(u0​)=−12⋅05+50⋅04−8⋅03+8⋅0+10=10u1​=−0.4
Δu1​=∣−0.4−0∣=0.4Δu1​=0.4
u2​=−0.45487…:Δu2​=0.05487…
f(u1​)=−2(−0.4)6+10(−0.4)5−2(−0.4)4+4(−0.4)2+10(−0.4)+4=0.478208f′(u1​)=−12(−0.4)5+50(−0.4)4−8(−0.4)3+8(−0.4)+10=8.71488u2​=−0.45487…
Δu2​=∣−0.45487…−(−0.4)∣=0.05487…Δu2​=0.05487…
u3​=−0.45285…:Δu3​=0.00201…
f(u2​)=−2(−0.45487…)6+10(−0.45487…)5−2(−0.45487…)4+4(−0.45487…)2+10(−0.45487…)+4=−0.01916…f′(u2​)=−12(−0.45487…)5+50(−0.45487…)4−8(−0.45487…)3+8(−0.45487…)+10=9.48821…u3​=−0.45285…
Δu3​=∣−0.45285…−(−0.45487…)∣=0.00201…Δu3​=0.00201…
u4​=−0.45284…:Δu4​=3.93806E−6
f(u3​)=−2(−0.45285…)6+10(−0.45285…)5−2(−0.45285…)4+4(−0.45285…)2+10(−0.45285…)+4=−0.00003…f′(u3​)=−12(−0.45285…)5+50(−0.45285…)4−8(−0.45285…)3+8(−0.45285…)+10=9.45147…u4​=−0.45284…
Δu4​=∣−0.45284…−(−0.45285…)∣=3.93806E−6Δu4​=3.93806E−6
u5​=−0.45284…:Δu5​=1.47831E−11
f(u4​)=−2(−0.45284…)6+10(−0.45284…)5−2(−0.45284…)4+4(−0.45284…)2+10(−0.45284…)+4=−1.39721E−10f′(u4​)=−12(−0.45284…)5+50(−0.45284…)4−8(−0.45284…)3+8(−0.45284…)+10=9.45140…u5​=−0.45284…
Δu5​=∣−0.45284…−(−0.45284…)∣=1.47831E−11Δu5​=1.47831E−11
u≈−0.45284…
Aplicar a divisão longa Equation0:u+0.45284…−2u6+10u5−2u4+4u2+10u+4​=−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…
−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…≈0
Encontrar uma solução para −2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…=0 utilizando o método de Newton-Raphson:u≈4.82043…
−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…=0
Definição de método de Newton-Raphson
f(u)=−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…
Encontrar f′(u):−10u4+43.62278…u3−20.81589…u2+6.28430…u+2.57708…
dud​(−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…)
Aplicar a regra da soma/diferença: (f±g)′=f′±g′=−dud​(2u5)+dud​(10.90569…u4)−dud​(6.93863…u3)+dud​(3.14215…u2)+dud​(2.57708…u)+dud​(8.83297…)
dud​(2u5)=10u4
dud​(2u5)
Retirar a constante: (a⋅f)′=a⋅f′=2dud​(u5)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=2⋅5u5−1
Simplificar=10u4
dud​(10.90569…u4)=43.62278…u3
dud​(10.90569…u4)
Retirar a constante: (a⋅f)′=a⋅f′=10.90569…dud​(u4)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=10.90569…⋅4u4−1
Simplificar=43.62278…u3
dud​(6.93863…u3)=20.81589…u2
dud​(6.93863…u3)
Retirar a constante: (a⋅f)′=a⋅f′=6.93863…dud​(u3)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=6.93863…⋅3u3−1
Simplificar=20.81589…u2
dud​(3.14215…u2)=6.28430…u
dud​(3.14215…u2)
Retirar a constante: (a⋅f)′=a⋅f′=3.14215…dud​(u2)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=3.14215…⋅2u2−1
Simplificar=6.28430…u
dud​(2.57708…u)=2.57708…
dud​(2.57708…u)
Retirar a constante: (a⋅f)′=a⋅f′=2.57708…dudu​
Aplicar a regra da derivação: dudu​=1=2.57708…⋅1
Simplificar=2.57708…
dud​(8.83297…)=0
dud​(8.83297…)
Derivada de uma constante: dxd​(a)=0=0
=−10u4+43.62278…u3−20.81589…u2+6.28430…u+2.57708…+0
Simplificar=−10u4+43.62278…u3−20.81589…u2+6.28430…u+2.57708…
Seja u0​=−2Calcular un+1​ até que Δun+1​<0.000001
u1​=−1.48484…:Δu1​=0.51515…
f(u0​)=−2(−2)5+10.90569…(−2)4−6.93863…(−2)3+3.14215…(−2)2+2.57708…(−2)+8.83297…=310.24761…f′(u0​)=−10(−2)4+43.62278…(−2)3−20.81589…(−2)2+6.28430…(−2)+2.57708…=−602.23740…u1​=−1.48484…
Δu1​=∣−1.48484…−(−2)∣=0.51515…Δu1​=0.51515…
u2​=−1.06652…:Δu2​=0.41831…
f(u1​)=−2(−1.48484…)5+10.90569…(−1.48484…)4−6.93863…(−1.48484…)3+3.14215…(−1.48484…)2+2.57708…(−1.48484…)+8.83297…=102.09660…f′(u1​)=−10(−1.48484…)4+43.62278…(−1.48484…)3−20.81589…(−1.48484…)2+6.28430…(−1.48484…)+2.57708…=−244.06592…u2​=−1.06652…
Δu2​=∣−1.06652…−(−1.48484…)∣=0.41831…Δu2​=0.41831…
u3​=−0.69341…:Δu3​=0.37311…
f(u2​)=−2(−1.06652…)5+10.90569…(−1.06652…)4−6.93863…(−1.06652…)3+3.14215…(−1.06652…)2+2.57708…(−1.06652…)+8.83297…=34.94642…f′(u2​)=−10(−1.06652…)4+43.62278…(−1.06652…)3−20.81589…(−1.06652…)2+6.28430…(−1.06652…)+2.57708…=−93.66242…u3​=−0.69341…
Δu3​=∣−0.69341…−(−1.06652…)∣=0.37311…Δu3​=0.37311…
u4​=−0.21473…:Δu4​=0.47868…
f(u3​)=−2(−0.69341…)5+10.90569…(−0.69341…)4−6.93863…(−0.69341…)3+3.14215…(−0.69341…)2+2.57708…(−0.69341…)+8.83297…=13.71217…f′(u3​)=−10(−0.69341…)4+43.62278…(−0.69341…)3−20.81589…(−0.69341…)2+6.28430…(−0.69341…)+2.57708…=−28.64562…u4​=−0.21473…
Δu4​=∣−0.21473…−(−0.69341…)∣=0.47868…Δu4​=0.47868…
u5​=45.73243…:Δu5​=45.94716…
f(u4​)=−2(−0.21473…)5+10.90569…(−0.21473…)4−6.93863…(−0.21473…)3+3.14215…(−0.21473…)2+2.57708…(−0.21473…)+8.83297…=8.51727…f′(u4​)=−10(−0.21473…)4+43.62278…(−0.21473…)3−20.81589…(−0.21473…)2+6.28430…(−0.21473…)+2.57708…=−0.18537…u5​=45.73243…
Δu5​=∣45.73243…−(−0.21473…)∣=45.94716…Δu5​=45.94716…
u6​=36.82019…:Δu6​=8.91223…
f(u5​)=−2⋅45.73243…5+10.90569…⋅45.73243…4−6.93863…⋅45.73243…3+3.14215…⋅45.73243…2+2.57708…⋅45.73243…+8.83297…=−353037842.88944…f′(u5​)=−10⋅45.73243…4+43.62278…⋅45.73243…3−20.81589…⋅45.73243…2+6.28430…⋅45.73243…+2.57708…=−39612709.25671…u6​=36.82019…
Δu6​=∣36.82019…−45.73243…∣=8.91223…Δu6​=8.91223…
u7​=29.69478…:Δu7​=7.12541…
f(u6​)=−2⋅36.82019…5+10.90569…⋅36.82019…4−6.93863…⋅36.82019…3+3.14215…⋅36.82019…2+2.57708…⋅36.82019…+8.83297…=−115648118.63564…f′(u6​)=−10⋅36.82019…4+43.62278…⋅36.82019…3−20.81589…⋅36.82019…2+6.28430…⋅36.82019…+2.57708…=−16230376.60275…u7​=29.69478…
Δu7​=∣29.69478…−36.82019…∣=7.12541…Δu7​=7.12541…
u8​=24.00013…:Δu8​=5.69464…
f(u7​)=−2⋅29.69478…5+10.90569…⋅29.69478…4−6.93863…⋅29.69478…3+3.14215…⋅29.69478…2+2.57708…⋅29.69478…+8.83297…=−37876817.50021…f′(u7​)=−10⋅29.69478…4+43.62278…⋅29.69478…3−20.81589…⋅29.69478…2+6.28430…⋅29.69478…+2.57708…=−6651300.86677…u8​=24.00013…
Δu8​=∣24.00013…−29.69478…∣=5.69464…Δu8​=5.69464…
u9​=19.45186…:Δu9​=4.54827…
f(u8​)=−2⋅24.00013…5+10.90569…⋅24.00013…4−6.93863…⋅24.00013…3+3.14215…⋅24.00013…2+2.57708…⋅24.00013…+8.83297…=−12401417.47322…f′(u8​)=−10⋅24.00013…4+43.62278…⋅24.00013…3−20.81589…⋅24.00013…2+6.28430…⋅24.00013…+2.57708…=−2726621.64422…u9​=19.45186…
Δu9​=∣19.45186…−24.00013…∣=4.54827…Δu9​=4.54827…
u10​=15.82312…:Δu10​=3.62873…
f(u9​)=−2⋅19.45186…5+10.90569…⋅19.45186…4−6.93863…⋅19.45186…3+3.14215…⋅19.45186…2+2.57708…⋅19.45186…+8.83297…=−4058236.53789…f′(u9​)=−10⋅19.45186…4+43.62278…⋅19.45186…3−20.81589…⋅19.45186…2+6.28430…⋅19.45186…+2.57708…=−1118360.52689…u10​=15.82312…
Δu10​=∣15.82312…−19.45186…∣=3.62873…Δu10​=3.62873…
u11​=12.93345…:Δu11​=2.88967…
f(u10​)=−2⋅15.82312…5+10.90569…⋅15.82312…4−6.93863…⋅15.82312…3+3.14215…⋅15.82312…2+2.57708…⋅15.82312…+8.83297…=−1326791.95496…f′(u10​)=−10⋅15.82312…4+43.62278…⋅15.82312…3−20.81589…⋅15.82312…2+6.28430…⋅15.82312…+2.57708…=−459149.56948…u11​=12.93345…
Δu11​=∣12.93345…−15.82312…∣=2.88967…Δu11​=2.88967…
u12​=10.64002…:Δu12​=2.29343…
f(u11​)=−2⋅12.93345…5+10.90569…⋅12.93345…4−6.93863…⋅12.93345…3+3.14215…⋅12.93345…2+2.57708…⋅12.93345…+8.83297…=−433068.72392…f′(u11​)=−10⋅12.93345…4+43.62278…⋅12.93345…3−20.81589…⋅12.93345…2+6.28430…⋅12.93345…+2.57708…=−188829.97467…u12​=10.64002…
Δu12​=∣10.64002…−12.93345…∣=2.29343…Δu12​=2.29343…
u13​=8.83106…:Δu13​=1.80895…
f(u12​)=−2⋅10.64002…5+10.90569…⋅10.64002…4−6.93863…⋅10.64002…3+3.14215…⋅10.64002…2+2.57708…⋅10.64002…+8.83297…=−140929.23683…f′(u12​)=−10⋅10.64002…4+43.62278…⋅10.64002…3−20.81589…⋅10.64002…2+6.28430…⋅10.64002…+2.57708…=−77906.25228…u13​=8.83106…
Δu13​=∣8.83106…−10.64002…∣=1.80895…Δu13​=1.80895…
u14​=7.42130…:Δu14​=1.40976…
f(u13​)=−2⋅8.83106…5+10.90569…⋅8.83106…4−6.93863…⋅8.83106…3+3.14215…⋅8.83106…2+2.57708…⋅8.83106…+8.83297…=−45595.29435…f′(u13​)=−10⋅8.83106…4+43.62278…⋅8.83106…3−20.81589…⋅8.83106…2+6.28430…⋅8.83106…+2.57708…=−32342.49741…u14​=7.42130…
Δu14​=∣7.42130…−8.83106…∣=1.40976…Δu14​=1.40976…
u15​=6.34950…:Δu15​=1.07179…
f(u14​)=−2⋅7.42130…5+10.90569…⋅7.42130…4−6.93863…⋅7.42130…3+3.14215…⋅7.42130…2+2.57708…⋅7.42130…+8.83297…=−14576.98569…f′(u14​)=−10⋅7.42130…4+43.62278…⋅7.42130…3−20.81589…⋅7.42130…2+6.28430…⋅7.42130…+2.57708…=−13600.48355…u15​=6.34950…
Δu15​=∣6.34950…−7.42130…∣=1.07179…Δu15​=1.07179…
u16​=5.57803…:Δu16​=0.77146…
f(u15​)=−2⋅6.34950…5+10.90569…⋅6.34950…4−6.93863…⋅6.34950…3+3.14215…⋅6.34950…2+2.57708…⋅6.34950…+8.83297…=−4539.15945…f′(u15​)=−10⋅6.34950…4+43.62278…⋅6.34950…3−20.81589…⋅6.34950…2+6.28430…⋅6.34950…+2.57708…=−5883.78460…u16​=5.57803…
Δu16​=∣5.57803…−6.34950…∣=0.77146…Δu16​=0.77146…
u17​=5.09067…:Δu17​=0.48736…
f(u16​)=−2⋅5.57803…5+10.90569…⋅5.57803…4−6.93863…⋅5.57803…3+3.14215…⋅5.57803…2+2.57708…⋅5.57803…+8.83297…=−1325.66062…f′(u16​)=−10⋅5.57803…4+43.62278…⋅5.57803…3−20.81589…⋅5.57803…2+6.28430…⋅5.57803…+2.57708…=−2720.07531…u17​=5.09067…
Δu17​=∣5.09067…−5.57803…∣=0.48736…Δu17​=0.48736…
u18​=4.86858…:Δu18​=0.22208…
f(u17​)=−2⋅5.09067…5+10.90569…⋅5.09067…4−6.93863…⋅5.09067…3+3.14215…⋅5.09067…2+2.57708…⋅5.09067…+8.83297…=−325.52900…f′(u17​)=−10⋅5.09067…4+43.62278…⋅5.09067…3−20.81589…⋅5.09067…2+6.28430…⋅5.09067…+2.57708…=−1465.80116…u18​=4.86858…
Δu18​=∣4.86858…−5.09067…∣=0.22208…Δu18​=0.22208…
u19​=4.82230…:Δu19​=0.04628…
f(u18​)=−2⋅4.86858…5+10.90569…⋅4.86858…4−6.93863…⋅4.86858…3+3.14215…⋅4.86858…2+2.57708…⋅4.86858…+8.83297…=−48.34478…f′(u18​)=−10⋅4.86858…4+43.62278…⋅4.86858…3−20.81589…⋅4.86858…2+6.28430…⋅4.86858…+2.57708…=−1044.51538…u19​=4.82230…
Δu19​=∣4.82230…−4.86858…∣=0.04628…Δu19​=0.04628…
u20​=4.82043…:Δu20​=0.00186…
f(u19​)=−2⋅4.82230…5+10.90569…⋅4.82230…4−6.93863…⋅4.82230…3+3.14215…⋅4.82230…2+2.57708…⋅4.82230…+8.83297…=−1.80563…f′(u19​)=−10⋅4.82230…4+43.62278…⋅4.82230…3−20.81589…⋅4.82230…2+6.28430…⋅4.82230…+2.57708…=−967.05976…u20​=4.82043…
Δu20​=∣4.82043…−4.82230…∣=0.00186…Δu20​=0.00186…
u21​=4.82043…:Δu21​=2.95792E−6
f(u20​)=−2⋅4.82043…5+10.90569…⋅4.82043…4−6.93863…⋅4.82043…3+3.14215…⋅4.82043…2+2.57708…⋅4.82043…+8.83297…=−0.00285…f′(u20​)=−10⋅4.82043…4+43.62278…⋅4.82043…3−20.81589…⋅4.82043…2+6.28430…⋅4.82043…+2.57708…=−964.00633…u21​=4.82043…
Δu21​=∣4.82043…−4.82043…∣=2.95792E−6Δu21​=2.95792E−6
u22​=4.82043…:Δu22​=7.4149E−12
f(u21​)=−2⋅4.82043…5+10.90569…⋅4.82043…4−6.93863…⋅4.82043…3+3.14215…⋅4.82043…2+2.57708…⋅4.82043…+8.83297…=−7.14797E−9f′(u21​)=−10⋅4.82043…4+43.62278…⋅4.82043…3−20.81589…⋅4.82043…2+6.28430…⋅4.82043…+2.57708…=−964.00149…u22​=4.82043…
Δu22​=∣4.82043…−4.82043…∣=7.4149E−12Δu22​=7.4149E−12
u≈4.82043…
Aplicar a divisão longa Equation0:u−4.82043…−2u5+10.90569…u4−6.93863…u3+3.14215…u2+2.57708…u+8.83297…​=−2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…
−2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…≈0
Encontrar uma solução para −2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…=0 utilizando o método de Newton-Raphson:Sem solução para u∈R
−2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…=0
Definição de método de Newton-Raphson
f(u)=−2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…
Encontrar f′(u):−8u3+3.79448…u2−1.68320…u−0.91474…
dud​(−2u4+1.26482…u3−0.84160…u2−0.91474…u−1.83240…)
Aplicar a regra da soma/diferença: (f±g)′=f′±g′=−dud​(2u4)+dud​(1.26482…u3)−dud​(0.84160…u2)−dud​(0.91474…u)−dud​(1.83240…)
dud​(2u4)=8u3
dud​(2u4)
Retirar a constante: (a⋅f)′=a⋅f′=2dud​(u4)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=2⋅4u4−1
Simplificar=8u3
dud​(1.26482…u3)=3.79448…u2
dud​(1.26482…u3)
Retirar a constante: (a⋅f)′=a⋅f′=1.26482…dud​(u3)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=1.26482…⋅3u3−1
Simplificar=3.79448…u2
dud​(0.84160…u2)=1.68320…u
dud​(0.84160…u2)
Retirar a constante: (a⋅f)′=a⋅f′=0.84160…dud​(u2)
Aplicar a regra da potência: dxd​(xa)=a⋅xa−1=0.84160…⋅2u2−1
Simplificar=1.68320…u
dud​(0.91474…u)=0.91474…
dud​(0.91474…u)
Retirar a constante: (a⋅f)′=a⋅f′=0.91474…dudu​
Aplicar a regra da derivação: dudu​=1=0.91474…⋅1
Simplificar=0.91474…
dud​(1.83240…)=0
dud​(1.83240…)
Derivada de uma constante: dxd​(a)=0=0
=−8u3+3.79448…u2−1.68320…u−0.91474…−0
Simplificar=−8u3+3.79448…u2−1.68320…u−0.91474…
Seja u0​=−2Calcular un+1​ até que Δun+1​<0.000001
u1​=−1.44275…:Δu1​=0.55724…
f(u0​)=−2(−2)4+1.26482…(−2)3−0.84160…(−2)2−0.91474…(−2)−1.83240…=−45.48795…f′(u0​)=−8(−2)3+3.79448…(−2)2−1.68320…(−2)−0.91474…=81.62962…u1​=−1.44275…
Δu1​=∣−1.44275…−(−2)∣=0.55724…Δu1​=0.55724…
u2​=−1.00226…:Δu2​=0.44048…
f(u1​)=−2(−1.44275…)4+1.26482…(−1.44275…)3−0.84160…(−1.44275…)2−0.91474…(−1.44275…)−1.83240…=−14.72848…f′(u1​)=−8(−1.44275…)3+3.79448…(−1.44275…)2−1.68320…(−1.44275…)−0.91474…=33.43713…u2​=−1.00226…
Δu2​=∣−1.00226…−(−1.44275…)∣=0.44048…Δu2​=0.44048…
u3​=−0.60248…:Δu3​=0.39978…
f(u2​)=−2(−1.00226…)4+1.26482…(−1.00226…)3−0.84160…(−1.00226…)2−0.91474…(−1.00226…)−1.83240…=−5.05267…f′(u2​)=−8(−1.00226…)3+3.79448…(−1.00226…)2−1.68320…(−1.00226…)−0.91474…=12.63858…u3​=−0.60248…
Δu3​=∣−0.60248…−(−1.00226…)∣=0.39978…Δu3​=0.39978…
u4​=0.05675…:Δu4​=0.65924…
f(u3​)=−2(−0.60248…)4+1.26482…(−0.60248…)3−0.84160…(−0.60248…)2−0.91474…(−0.60248…)−1.83240…=−2.12691…f′(u3​)=−8(−0.60248…)3+3.79448…(−0.60248…)2−1.68320…(−0.60248…)−0.91474…=3.22630…u4​=0.05675…
Δu4​=∣0.05675…−(−0.60248…)∣=0.65924…Δu4​=0.65924…
u5​=−1.83097…:Δu5​=1.88772…
f(u4​)=−2⋅0.05675…4+1.26482…⋅0.05675…3−0.84160…⋅0.05675…2−0.91474…⋅0.05675…−1.83240…=−1.88681…f′(u4​)=−8⋅0.05675…3+3.79448…⋅0.05675…2−1.68320…⋅0.05675…−0.91474…=−0.99951…u5​=−1.83097…
Δu5​=∣−1.83097…−0.05675…∣=1.88772…Δu5​=1.88772…
u6​=−1.31185…:Δu6​=0.51912…
f(u5​)=−2(−1.83097…)4+1.26482…(−1.83097…)3−0.84160…(−1.83097…)2−0.91474…(−1.83097…)−1.83240…=−33.22099…f′(u5​)=−8(−1.83097…)3+3.79448…(−1.83097…)2−1.68320…(−1.83097…)−0.91474…=63.99442…u6​=−1.31185…
Δu6​=∣−1.31185…−(−1.83097…)∣=0.51912…Δu6​=0.51912…
u7​=−0.89231…:Δu7​=0.41954…
f(u6​)=−2(−1.31185…)4+1.26482…(−1.31185…)3−0.84160…(−1.31185…)2−0.91474…(−1.31185…)−1.83240…=−10.85966…f′(u6​)=−8(−1.31185…)3+3.79448…(−1.31185…)2−1.68320…(−1.31185…)−0.91474…=25.88464…u7​=−0.89231…
Δu7​=∣−0.89231…−(−1.31185…)∣=0.41954…Δu7​=0.41954…
u8​=−0.47768…:Δu8​=0.41462…
f(u7​)=−2(−0.89231…)4+1.26482…(−0.89231…)3−0.84160…(−0.89231…)2−0.91474…(−0.89231…)−1.83240…=−3.85282…f′(u7​)=−8(−0.89231…)3+3.79448…(−0.89231…)2−1.68320…(−0.89231…)−0.91474…=9.29225…u8​=−0.47768…
Δu8​=∣−0.47768…−(−0.89231…)∣=0.41462…Δu8​=0.41462…
u9​=0.64668…:Δu9​=1.12436…
f(u8​)=−2(−0.47768…)4+1.26482…(−0.47768…)3−0.84160…(−0.47768…)2−0.91474…(−0.47768…)−1.83240…=−1.82947…f′(u8​)=−8(−0.47768…)3+3.79448…(−0.47768…)2−1.68320…(−0.47768…)−0.91474…=1.62711…u9​=0.64668…
Δu9​=∣0.64668…−(−0.47768…)∣=1.12436…Δu9​=1.12436…
u10​=−0.43226…:Δu10​=1.07894…
f(u9​)=−2⋅0.64668…4+1.26482…⋅0.64668…3−0.84160…⋅0.64668…2−0.91474…⋅0.64668…−1.83240…=−2.78363…f′(u9​)=−8⋅0.64668…3+3.79448…⋅0.64668…2−1.68320…⋅0.64668…−0.91474…=−2.57995…u10​=−0.43226…
Δu10​=∣−0.43226…−0.64668…∣=1.07894…Δu10​=1.07894…
u11​=1.07993…:Δu11​=1.51219…
f(u10​)=−2(−0.43226…)4+1.26482…(−0.43226…)3−0.84160…(−0.43226…)2−0.91474…(−0.43226…)−1.83240…=−1.76622…f′(u10​)=−8(−0.43226…)3+3.79448…(−0.43226…)2−1.68320…(−0.43226…)−0.91474…=1.16798…u11​=1.07993…
Δu11​=∣1.07993…−(−0.43226…)∣=1.51219…Δu11​=1.51219…
Não se pode encontrar solução
As soluções sãou≈−0.45284…,u≈4.82043…
u≈−0.45284…,u≈4.82043…
Verifique soluções
Encontrar os pontos não definidos (singularidades):u=0
Tomar o(s) denominador(es) de 3u2+u−2u2−u−2​ e comparar com zero
Resolver u2=0:u=0
u2=0
Aplicar a regra xn=0⇒x=0
u=0
Tomar o(s) denominador(es) de 5u+u−12​+1 e comparar com zero
u=0
Os seguintes pontos são indefinidosu=0
Combinar os pontos indefinidos com as soluções:
u≈−0.45284…,u≈4.82043…
u≈−0.45284…,u≈4.82043…
Substitua u=eθ,solucione para θ
Resolver eθ=−0.45284…:Sem solução para θ∈R
eθ=−0.45284…
af(θ) não pode ser zero ou negativa para θ∈RSemsoluc\c​a~oparaθ∈R
Resolver eθ=4.82043…:θ=ln(4.82043…)
eθ=4.82043…
Aplicar as propriedades dos expoentes
eθ=4.82043…
Se f(x)=g(x), então ln(f(x))=ln(g(x))ln(eθ)=ln(4.82043…)
Aplicar as propriedades dos logaritmos: ln(ea)=aln(eθ)=θθ=ln(4.82043…)
θ=ln(4.82043…)
θ=ln(4.82043…)
θ=ln(4.82043…)

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