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受欢迎的三角函数 >

1=cos(((pi(t-22)))/(183))

解答

1 = cos (\frac{( π ( t - 22 ) )}{183})

解答

t = 366 n + 22

+1

度数

t = 1260.50714 \dots^{\circ} + 20970.25530 \dots^{\circ} n

求解步骤

1 = cos (\frac{( π ( t - 22 ) )}{183})

交换两边

cos (\frac{π ( t - 22 )}{183}) = 1

cos (\frac{π ( t - 22 )}{183}) = 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

\frac{π ( t - 22 )}{183} = 0 + 2 πn

\frac{π ( t - 22 )}{183} = 0 + 2 πn

解

\frac{π ( t - 22 )}{183} = 0 + 2 πn : t = 366 n + 22

\frac{π ( t - 22 )}{183} = 0 + 2 πn

0 + 2 πn = 2 πn

\frac{π ( t - 22 )}{183} = 2 πn

在两边乘以

183

\frac{π ( t - 22 )}{183} = 2 πn

在两边乘以

183

\frac{183 π ( t - 22 )}{183} = 183 \cdot 2 πn

化简

π (t - 22) = 366 πn

π (t - 22) = 366 πn

两边除以

π

π (t - 22) = 366 πn

两边除以

π

\frac{π ( t - 22 )}{π} = \frac{366 πn}{π}

化简

t - 22 = 366 n

t - 22 = 366 n

将

22

到右边

t - 22 = 366 n

两边加上

22

t - 22 + 22 = 366 n + 22

化简

t = 366 n + 22

t = 366 n + 22

t = 366 n + 22

作图

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