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人気のある三角関数 >

tan(θ)=(cos(θ))/(sin(θ))

解

tan (θ) = \frac{cos ( θ )}{sin ( θ )}

解

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

+1

度

θ = 4 5^{\circ} + 18 0^{\circ} n, θ = 13 5^{\circ} + 18 0^{\circ} n

解答ステップ

tan (θ) = \frac{cos ( θ )}{sin ( θ )}

両辺から

\frac{cos ( θ )}{sin ( θ )}

を引く

tan (θ) - \frac{cos ( θ )}{sin ( θ )} = 0

簡素化

tan (θ) - \frac{cos ( θ )}{sin ( θ )} : \frac{tan ( θ ) sin ( θ ) - cos ( θ )}{sin ( θ )}

tan (θ) - \frac{cos ( θ )}{sin ( θ )}

元を分数に変換する:

tan (θ) = \frac{tan ( θ ) sin ( θ )}{sin ( θ )}

= \frac{tan ( θ ) sin ( θ )}{sin ( θ )} - \frac{cos ( θ )}{sin ( θ )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{tan ( θ ) sin ( θ ) - cos ( θ )}{sin ( θ )}

\frac{tan ( θ ) sin ( θ ) - cos ( θ )}{sin ( θ )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

tan (θ) sin (θ) - cos (θ) = 0

サイン, コサインで表わす

- cos (θ) + sin (θ) tan (θ)

基本的な三角関数の公式を使用する:

tan (x) = \frac{sin ( x )}{cos ( x )}

= - cos (θ) + sin (θ) \frac{sin ( θ )}{cos ( θ )}

簡素化

- cos (θ) + sin (θ) \frac{sin ( θ )}{cos ( θ )} : \frac{- cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ( θ )}

- cos (θ) + sin (θ) \frac{sin ( θ )}{cos ( θ )}

sin (θ) \frac{sin ( θ )}{cos ( θ )} = \frac{sin ^{2} ( θ )}{cos ( θ )}

sin (θ) \frac{sin ( θ )}{cos ( θ )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( θ ) sin ( θ )}{cos ( θ )}

sin (θ) sin (θ) = sin^{2} (θ)

sin (θ) sin (θ)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

sin (θ) sin (θ) = sin^{1 + 1} (θ)

= sin^{1 + 1} (θ)

数を足す:

1 + 1 = 2

= sin^{2} (θ)

= \frac{sin ^{2} ( θ )}{cos ( θ )}

= - cos (θ) + \frac{sin ^{2} ( θ )}{cos ( θ )}

元を分数に変換する:

cos (θ) = \frac{cos ( θ ) cos ( θ )}{cos ( θ )}

= - \frac{cos ( θ ) cos ( θ )}{cos ( θ )} + \frac{sin ^{2} ( θ )}{cos ( θ )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- cos ( θ ) cos ( θ ) + sin ^{2} ( θ )}{cos ( θ )}

- cos (θ) cos (θ) + sin^{2} (θ) = - cos^{2} (θ) + sin^{2} (θ)

- cos (θ) cos (θ) + sin^{2} (θ)

cos (θ) cos (θ) = cos^{2} (θ)

cos (θ) cos (θ)

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

cos (θ) cos (θ) = cos^{1 + 1} (θ)

= cos^{1 + 1} (θ)

数を足す:

1 + 1 = 2

= cos^{2} (θ)

= - cos^{2} (θ) + sin^{2} (θ)

= \frac{- cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ( θ )}

= \frac{- cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ( θ )}

\frac{- cos ^{2} ( θ ) + sin ^{2} ( θ )}{cos ( θ )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

- cos^{2} (θ) + sin^{2} (θ) = 0

三角関数の公式を使用して書き換える

- cos^{2} (θ) + sin^{2} (θ)

2倍角の公式を使用:

cos^{2} (x) - sin^{2} (x) = cos (2 x)

- cos^{2} (x) + sin^{2} (x) = - cos (2 x)

= - cos (2 θ)

- cos (2 θ) = 0

以下で両辺を割る

- 1

- cos (2 θ) = 0

以下で両辺を割る

- 1

\frac{- cos ( 2 θ )}{- 1} = \frac{0}{- 1}

簡素化

cos (2 θ) = 0

cos (2 θ) = 0

以下の一般解

cos (2 θ) = 0

cos (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

2 θ = \frac{π}{2} + 2 πn, 2 θ = \frac{3 π}{2} + 2 πn

解く

2 θ = \frac{π}{2} + 2 πn : θ = \frac{π}{4} + πn

2 θ = \frac{π}{2} + 2 πn

以下で両辺を割る

2

2 θ = \frac{π}{2} + 2 πn

以下で両辺を割る

2

\frac{2 θ}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 θ}{2} = \frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

数を割る:

\frac{2}{2} = 1

= θ

簡素化

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2} : \frac{π}{4} + πn

\frac{\frac{π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{π}{2}}{2} = \frac{π}{4}

\frac{\frac{π}{2}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

数を割る:

\frac{2}{2} = 1

= πn

= \frac{π}{4} + πn

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

θ = \frac{π}{4} + πn

解く

2 θ = \frac{3 π}{2} + 2 πn : θ = \frac{3 π}{4} + πn

2 θ = \frac{3 π}{2} + 2 πn

以下で両辺を割る

2

2 θ = \frac{3 π}{2} + 2 πn

以下で両辺を割る

2

\frac{2 θ}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 θ}{2} = \frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

簡素化

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

数を割る:

\frac{2}{2} = 1

= θ

簡素化

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2} : \frac{3 π}{4} + πn

\frac{\frac{3 π}{2}}{2} + \frac{2 πn}{2}

\frac{\frac{3 π}{2}}{2} = \frac{3 π}{4}

\frac{\frac{3 π}{2}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{3 π}{2 \cdot 2}

数を乗じる:

2 \cdot 2 = 4

= \frac{3 π}{4}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

数を割る:

\frac{2}{2} = 1

= πn

= \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

θ = \frac{3 π}{4} + πn

θ = \frac{π}{4} + πn, θ = \frac{3 π}{4} + πn

グラフ

人気の例

sin(θ)+2sin^2(θ)=0

sin (θ) + 2 sin^{2} (θ) = 0

(cot(x)+1)(sin(x)+1)=0

(cot (x) + 1) (sin (x) + 1) = 0

cos^2(x)-2sin(x)=0

cos^{2} (x) - 2 sin (x) = 0

sin(x)cos(2x)+cos(x)sin(2x)= 1/2

sin (x) cos (2 x) + cos (x) sin (2 x) = \frac{1}{2}

sin(3x)-3sin(x)=0

sin (3 x) - 3 sin (x) = 0