ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある三角関数 >

cos^2(x)=0.1

解

cos^{2} (x) = 0.1

解

x = 1.24904 \dots + 2 πn, x = 2 π - 1.24904 \dots + 2 πn, x = 1.89254 \dots + 2 πn, x = - 1.89254 \dots + 2 πn

+1

度

x = 71.56505 \dots^{\circ} + 36 0^{\circ} n, x = 288.43494 \dots^{\circ} + 36 0^{\circ} n, x = 108.43494 \dots^{\circ} + 36 0^{\circ} n, x = - 108.43494 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

cos^{2} (x) = 0.1

置換で解く

cos^{2} (x) = 0.1

仮定:

cos (x) = u

u^{2} = 0.1

u^{2} = 0.1 : u = 0.1, u = - 0.1

u^{2} = 0.1

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = 0.1, u = - 0.1

代用を戻す

u = cos (x)

cos (x) = 0.1, cos (x) = - 0.1

cos (x) = 0.1, cos (x) = - 0.1

cos (x) = 0.1 : x = arccos (0.1) + 2 πn, x = 2 π - arccos (0.1) + 2 πn

cos (x) = 0.1

三角関数の逆数プロパティを適用する

cos (x) = 0.1

以下の一般解

cos (x) = 0.1

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

x = arccos (0.1) + 2 πn, x = 2 π - arccos (0.1) + 2 πn

x = arccos (0.1) + 2 πn, x = 2 π - arccos (0.1) + 2 πn

cos (x) = - 0.1 : x = arccos (- 0.1) + 2 πn, x = - arccos (- 0.1) + 2 πn

cos (x) = - 0.1

三角関数の逆数プロパティを適用する

cos (x) = - 0.1

以下の一般解

cos (x) = - 0.1

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (- 0.1) + 2 πn, x = - arccos (- 0.1) + 2 πn

x = arccos (- 0.1) + 2 πn, x = - arccos (- 0.1) + 2 πn

すべての解を組み合わせる

x = arccos (0.1) + 2 πn, x = 2 π - arccos (0.1) + 2 πn, x = arccos (- 0.1) + 2 πn, x = - arccos (- 0.1) + 2 πn

10進法形式で解を証明する

x = 1.24904 \dots + 2 πn, x = 2 π - 1.24904 \dots + 2 πn, x = 1.89254 \dots + 2 πn, x = - 1.89254 \dots + 2 πn

グラフ

人気の例

cos (x) = 0.184

solvefor y,x=cos^2(y)

so l v e f or y, x = cos^{2} (y)

(10cos(2t+pi/6))=0

(10 cos (2 t + \frac{π}{6})) = 0

2sin(x+1.2)-4.22=-4

2 sin (x + 1.2) - 4.22 = - 4

-2sqrt(3)sin(x)+2cos(x)=0

- 23 sin (x) + 2 cos (x) = 0