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受欢迎的三角函数 >

cos(θ)=(13)/(sqrt(6)*\sqrt{86)}

解答

cos (θ) = \frac{13}{6 \cdot 86}

解答

θ = 0.96149 \dots + 2 πn, θ = 2 π - 0.96149 \dots + 2 πn

+1

弧度

θ = 0.96149 \dots + 6.28318 \dots n, θ = 5.32168 \dots + 6.28318 \dots n

求解步骤

cos (θ) = \frac{13}{6 86}

化简

\frac{13}{6 86} : \frac{13 129}{258}

\frac{13}{6 86}

化简

686 : 2343

686

分解整数

6 = 2 \cdot 3

= 2 \cdot 3 86

使用根式运算法则:

n ab = n a n b

2 \cdot 3 = 23

= 2386

分解整数

86 = 2 \cdot 43

= 23 2 \cdot 43

使用根式运算法则:

n ab = n a n b

2 \cdot 43 = 243

= 23243

使用根式运算法则:

a a = a

22 = 2

= 2343

= \frac{13}{2 3 43}

化简

3 \cdot 243 : 2129

3 \cdot 243

使用根式运算法则:

a b = a \cdot b

343 = 3 \cdot 43

= 2 3 \cdot 43

数字相乘:

3 \cdot 43 = 129

= 2129

= \frac{13}{2 129}

\frac{13}{2 129}

有理化:

\frac{13 129}{258}

\frac{13}{2 129}

乘以共轭根式

\frac{129}{129}

= \frac{13 129}{129 \cdot 2 129}

129 \cdot 2129 = 258

129 \cdot 2129

使用根式运算法则:

a a = a

129129 = 129

= 2 \cdot 129

数字相乘:

2 \cdot 129 = 258

= 258

= \frac{13 129}{258}

= \frac{13 129}{258}

cos (θ) = \frac{13 129}{258}

使用反三角函数性质

cos (θ) = \frac{13 129}{258}

cos (θ) = \frac{13 129}{258}

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

θ = arccos (\frac{13 129}{258}) + 2 πn, θ = 2 π - arccos (\frac{13 129}{258}) + 2 πn

θ = arccos (\frac{13 129}{258}) + 2 πn, θ = 2 π - arccos (\frac{13 129}{258}) + 2 πn

以小数形式表示解

θ = 0.96149 \dots + 2 πn, θ = 2 π - 0.96149 \dots + 2 πn

作图

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