csc(θ)=-2,0<= θ<4pi

Lösung

csc (θ) = - 2, 0 \leq θ < 4 π

θ = \frac{7 π}{6}, θ = \frac{11 π}{6}, θ = \frac{19 π}{6}, θ = \frac{23 π}{6}

Grad

θ = 21 0^{\circ}, θ = 33 0^{\circ}, θ = 57 0^{\circ}, θ = 69 0^{\circ}

Schritte zur Lösung

csc (θ) = - 2, 0 \leq θ < 4 π

Allgemeine Lösung für

csc (θ) = - 2

csc (x)

Periodizitätstabelle mit

2 πn

Zyklus:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

θ = \frac{7 π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Lösungen für den Bereich

0 \leq θ < 4 π

θ = \frac{7 π}{6}, θ = \frac{11 π}{6}, θ = \frac{19 π}{6}, θ = \frac{23 π}{6}

tan (x) + cot (x) = 5

5 sin^{2} (θ) + 12 sin (θ) + 7 = 0

3 sin (x) + 2 sin^{2} (x) = - 1

3 cos^{2} (x) - 2 cos (x) - 2 = 0, 0 \leq x < 2 π

sin (x + \frac{π}{4}) + sin (x - \frac{π}{4}) + \frac{6}{2} = 0