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人気のある三角関数 >

((6)^2sin^2(30))/(9.8)

解

\frac{( 6 ) ^{2} sin ^{2} ( 3 0 ^{\circ} )}{9.8}

解

\frac{45}{49}

+1

十進法表記

0.91836 \dots

解答ステップ

\frac{( 6 ) ^{2} sin ^{2} ( 3 0 ^{\circ} )}{9.8}

= \frac{6 ^{2} sin ^{2} ( 3 0 ^{\circ} )}{\frac{49}{5}}

次の自明恒等式を使用する:

sin (3 0^{\circ}) = \frac{1}{2}

sin (3 0^{\circ})

sin (x)

36 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= \frac{1}{2}

= \frac{6 ^{2} ( \frac{1}{2} ) ^{2}}{\frac{49}{5}}

簡素化

\frac{6 ^{2} ( \frac{1}{2} ) ^{2}}{\frac{49}{5}} : \frac{45}{49}

\frac{6 ^{2} ( \frac{1}{2} ) ^{2}}{\frac{49}{5}}

分数の規則を適用する:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{6 ^{2} ( \frac{1}{2} ) ^{2} \cdot 5}{49}

(\frac{1}{2})^{2} = \frac{1}{2 ^{2}}

(\frac{1}{2})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{1 ^{2}}{2 ^{2}}

規則を適用

1^{a} = 1

1^{2} = 1

= \frac{1}{2 ^{2}}

= \frac{6 ^{2} \cdot 5 \cdot \frac{1}{2 ^{2}}}{49}

乗じる

6^{2} \cdot \frac{1}{2 ^{2}} \cdot 5 : 45

6^{2} \cdot \frac{1}{2 ^{2}} \cdot 5

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 6 ^{2} \cdot 5}{2 ^{2}}

数を乗じる:

1 \cdot 5 = 5

= \frac{6 ^{2} \cdot 5}{2 ^{2}}

因数

6^{2} : 2^{2} \cdot 3^{2}

因数

6 = 2 \cdot 3

= (2 \cdot 3)^{2}

指数の規則を適用する:

(ab)^{c} = a^{c} b^{c}

= 2^{2} \cdot 3^{2}

= \frac{2 ^{2} \cdot 3 ^{2} \cdot 5}{2 ^{2}}

共通因数を約分する:

2^{2}

= 3^{2} \cdot 5

3^{2} = 9

= 9 \cdot 5

数を乗じる:

9 \cdot 5 = 45

= 45

= \frac{45}{49}

= \frac{45}{49}

人気の例

arctan(4/(sqrt(6)))

arctan (\frac{4}{6})

2arcsin(1.5*sin(0.14))

2 arcsin (1.5 \cdot sin (0.14))

(sin(30)+csc(30))/(sin^2(30)+cos^2(60))

\frac{sin ( 3 0 ^{\circ} ) + csc ( 3 0 ^{\circ} )}{sin ^{2} ( 3 0 ^{\circ} ) + cos ^{2} ( 6 0 ^{\circ} )}

(cos(12))/(1.17)

\frac{cos ( 1 2 ^{\circ} )}{1.17}

8 \cdot cos^{2} (3 0^{\circ})