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人気のある三角関数 >

tan(2θ)=-sqrt(3),0<= θ<= 360

解

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

解

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

+1

ラジアン

θ = \frac{π}{3}, θ = \frac{5 π}{6}, θ = \frac{4 π}{3}, θ = \frac{11 π}{6}

解答ステップ

tan (2 θ) = - 3, 0^{\circ} \leq θ \leq 36 0^{\circ}

以下の一般解

tan (2 θ) = - 3

tan (x)

18 0^{\circ} n

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

2 θ = 12 0^{\circ} + 18 0^{\circ} n

2 θ = 12 0^{\circ} + 18 0^{\circ} n

解く

2 θ = 12 0^{\circ} + 18 0^{\circ} n : θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

2 θ = 12 0^{\circ} + 18 0^{\circ} n

以下で両辺を割る

2

2 θ = 12 0^{\circ} + 18 0^{\circ} n

以下で両辺を割る

2

\frac{2 θ}{2} = \frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

簡素化

\frac{2 θ}{2} = \frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

簡素化

\frac{2 θ}{2} : θ

\frac{2 θ}{2}

数を割る:

\frac{2}{2} = 1

= θ

簡素化

\frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} : 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

\frac{12 0 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2}

\frac{12 0 ^{\circ}}{2} = 6 0^{\circ}

\frac{12 0 ^{\circ}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{36 0 ^{\circ}}{3 \cdot 2}

数を乗じる:

3 \cdot 2 = 6

= 6 0^{\circ}

共通因数を約分する:

2

= 6 0^{\circ}

= 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

θ = 6 0^{\circ} + \frac{18 0 ^{\circ} n}{2}

範囲の解答

0 \leq θ \leq 36 0^{\circ}

θ = 6 0^{\circ}, θ = 15 0^{\circ}, θ = 24 0^{\circ}, θ = 33 0^{\circ}

グラフ

人気の例

cos(t)-cos(2t)=0

cos (t) - cos (2 t) = 0

cot(2x)=-1,(0,2pi)

cot (2 x) = - 1, (0, 2 π)

sec^2(x)+4sec(x)-12=0

sec^{2} (x) + 4 sec (x) - 12 = 0

sin(θ)=-1,0<= θ<360

sin (θ) = - 1, 0^{\circ} \leq θ < 36 0^{\circ}

sin (x) = 7