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人気のある三角関数 >

6cos(2x)=6cos^2(x)-5

解

6 cos (2 x) = 6 cos^{2} (x) - 5

解

x = 1.15026 \dots + 2 πn, x = π - 1.15026 \dots + 2 πn, x = - 1.15026 \dots + 2 πn, x = π + 1.15026 \dots + 2 πn

+1

度

x = 65.90515 \dots^{\circ} + 36 0^{\circ} n, x = 114.09484 \dots^{\circ} + 36 0^{\circ} n, x = - 65.90515 \dots^{\circ} + 36 0^{\circ} n, x = 245.90515 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

6 cos (2 x) = 6 cos^{2} (x) - 5

両辺から

6 cos^{2} (x) - 5

を引く

6 cos (2 x) - 6 cos^{2} (x) + 5 = 0

三角関数の公式を使用して書き換える

5 + 6 cos (2 x) - 6 cos^{2} (x)

2倍角の公式を使用:

cos^{2} (x) - sin^{2} (x) = cos (2 x)

cos^{2} (x) = cos (2 x) + sin^{2} (x)

= 5 + 6 cos (2 x) - 6 (cos (2 x) + sin^{2} (x))

簡素化

5 + 6 cos (2 x) - 6 (cos (2 x) + sin^{2} (x)) : 5 - 6 sin^{2} (x)

5 + 6 cos (2 x) - 6 (cos (2 x) + sin^{2} (x))

拡張

- 6 (cos (2 x) + sin^{2} (x)) : - 6 cos (2 x) - 6 sin^{2} (x)

- 6 (cos (2 x) + sin^{2} (x))

分配法則を適用する:

a (b + c) = ab + a c

a = - 6, b = cos (2 x), c = sin^{2} (x)

= - 6 cos (2 x) + (- 6) sin^{2} (x)

マイナス・プラスの規則を適用する

+ (- a) = - a

= - 6 cos (2 x) - 6 sin^{2} (x)

= 5 + 6 cos (2 x) - 6 cos (2 x) - 6 sin^{2} (x)

類似した元を足す:

6 cos (2 x) - 6 cos (2 x) = 0

= 5 - 6 sin^{2} (x)

= 5 - 6 sin^{2} (x)

5 - 6 sin^{2} (x) = 0

置換で解く

5 - 6 sin^{2} (x) = 0

仮定:

sin (x) = u

5 - 6 u^{2} = 0

5 - 6 u^{2} = 0 : u = \frac{5}{6}, u = - \frac{5}{6}

5 - 6 u^{2} = 0

5

を右側に移動します

5 - 6 u^{2} = 0

両辺から

5

を引く

5 - 6 u^{2} - 5 = 0 - 5

簡素化

- 6 u^{2} = - 5

- 6 u^{2} = - 5

以下で両辺を割る

- 6

- 6 u^{2} = - 5

以下で両辺を割る

- 6

\frac{- 6 u ^{2}}{- 6} = \frac{- 5}{- 6}

簡素化

u^{2} = \frac{5}{6}

u^{2} = \frac{5}{6}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

u = \frac{5}{6}, u = - \frac{5}{6}

代用を戻す

u = sin (x)

sin (x) = \frac{5}{6}, sin (x) = - \frac{5}{6}

sin (x) = \frac{5}{6}, sin (x) = - \frac{5}{6}

sin (x) = \frac{5}{6} : x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = \frac{5}{6}

三角関数の逆数プロパティを適用する

sin (x) = \frac{5}{6}

以下の一般解

sin (x) = \frac{5}{6}

sin (x) = a \Rightarrow x = arcsin (a) + 2 πn, x = π - arcsin (a) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn

sin (x) = - \frac{5}{6} : x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

sin (x) = - \frac{5}{6}

三角関数の逆数プロパティを適用する

sin (x) = - \frac{5}{6}

以下の一般解

sin (x) = - \frac{5}{6}

sin (x) = - a \Rightarrow x = arcsin (- a) + 2 πn, x = π + arcsin (a) + 2 πn

x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

すべての解を組み合わせる

x = arcsin (\frac{5}{6}) + 2 πn, x = π - arcsin (\frac{5}{6}) + 2 πn, x = arcsin (- \frac{5}{6}) + 2 πn, x = π + arcsin (\frac{5}{6}) + 2 πn

10進法形式で解を証明する

x = 1.15026 \dots + 2 πn, x = π - 1.15026 \dots + 2 πn, x = - 1.15026 \dots + 2 πn, x = π + 1.15026 \dots + 2 πn

グラフ

人気の例

(-4cos(x)-6sin(x))^2-20sin^2(x)=16

(- 4 cos (x) - 6 sin (x))^{2} - 20 sin^{2} (x) = 16

sin (u) = \frac{5}{13}

0.8 = cos (x)

cos (x) = \frac{12}{20}

2sin^2(x)+sin(x)=1,-pi<= x<= pi

2 sin^{2} (x) + sin (x) = 1, - π \leq x \leq π