zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的三角函数 >

solvefor x,cos^2(x)=4p+6

解答

求解

x, cos^{2} (x) = 4 p + 6

解答

x = arccos (4 p + 6) + 2 πn, x = - arccos (4 p + 6) + 2 πn, x = arccos (- 4 p + 6) + 2 πn, x = - arccos (- 4 p + 6) + 2 πn

求解步骤

cos^{2} (x) = 4 p + 6

用替代法求解

cos^{2} (x) = 4 p + 6

令

: cos (x) = u

u^{2} = 4 p + 6

u^{2} = 4 p + 6 : u = 4 p + 6, u = - 4 p + 6

u^{2} = 4 p + 6

对于

x^{2} = f (a)

解为

x = f (a), - f (a)

u = 4 p + 6, u = - 4 p + 6

u = cos (x)

代回

cos (x) = 4 p + 6, cos (x) = - 4 p + 6

cos (x) = 4 p + 6, cos (x) = - 4 p + 6

cos (x) = 4 p + 6 : x = arccos (4 p + 6) + 2 πn, x = - arccos (4 p + 6) + 2 πn

cos (x) = 4 p + 6

使用反三角函数性质

cos (x) = 4 p + 6

cos (x) = 4 p + 6

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (4 p + 6) + 2 πn, x = - arccos (4 p + 6) + 2 πn

x = arccos (4 p + 6) + 2 πn, x = - arccos (4 p + 6) + 2 πn

cos (x) = - 4 p + 6 : x = arccos (- 4 p + 6) + 2 πn, x = - arccos (- 4 p + 6) + 2 πn

cos (x) = - 4 p + 6

使用反三角函数性质

cos (x) = - 4 p + 6

cos (x) = - 4 p + 6

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x = arccos (- 4 p + 6) + 2 πn, x = - arccos (- 4 p + 6) + 2 πn

x = arccos (- 4 p + 6) + 2 πn, x = - arccos (- 4 p + 6) + 2 πn

合并所有解

x = arccos (4 p + 6) + 2 πn, x = - arccos (4 p + 6) + 2 πn, x = arccos (- 4 p + 6) + 2 πn, x = - arccos (- 4 p + 6) + 2 πn

作图

流行的例子

2sin^2(x)-7sin(x)=0

2 sin^{2} (x) - 7 sin (x) = 0

sec (x) = \frac{1}{3}

solvefor x,u=cos(x^2y)

so l v e f or x, u = cos (x^{2} y)

6sin^2(x)-sin(x)cos(x)-2cos^2(x)=0

6 sin^{2} (x) - sin (x) cos (x) - 2 cos^{2} (x) = 0

tan(θ)=(20(9.8))/(25)

tan (θ) = \frac{20 ( 9.8 )}{25}