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شائع علم المثلثات >

tan(pi/2-x)+tan(x)-1=0

الحلّ

tan (\frac{π}{2} - x) + tan (x) - 1 = 0

الحلّ

x \in R لا يوجد حلّ لـ

خطوات الحلّ

tan (\frac{π}{2} - x) + tan (x) - 1 = 0

Rewrite using trig identities

tan (\frac{π}{2} - x) + tan (x) - 1 = 0

Rewrite using trig identities

tan (\frac{π}{2} - x)

tan (x) = \frac{sin ( x )}{cos ( x )}

:Use the basic trigonometric identity

= \frac{sin ( \frac{π}{2} - x )}{cos ( \frac{π}{2} - x )}

sin (s - t) = sin (s) cos (t) - cos (s) sin (t)

:فعّل متطابقة الطرح لزوايا

= \frac{sin ( \frac{π}{2} ) cos ( x ) - cos ( \frac{π}{2} ) sin ( x )}{cos ( \frac{π}{2} - x )}

cos (s - t) = cos (s) cos (t) + sin (s) sin (t)

:فعّل متطابقة الطرح لزوايا

= \frac{sin ( \frac{π}{2} ) cos ( x ) - cos ( \frac{π}{2} ) sin ( x )}{cos ( \frac{π}{2} ) cos ( x ) + sin ( \frac{π}{2} ) sin ( x )}

\frac{sin ( \frac{π}{2} ) cos ( x ) - cos ( \frac{π}{2} ) sin ( x )}{cos ( \frac{π}{2} ) cos ( x ) + sin ( \frac{π}{2} ) sin ( x )}

بسّط:

\frac{cos ( x )}{sin ( x )}

\frac{sin ( \frac{π}{2} ) cos ( x ) - cos ( \frac{π}{2} ) sin ( x )}{cos ( \frac{π}{2} ) cos ( x ) + sin ( \frac{π}{2} ) sin ( x )}

sin (\frac{π}{2}) cos (x) - cos (\frac{π}{2}) sin (x) = cos (x)

sin (\frac{π}{2}) cos (x) - cos (\frac{π}{2}) sin (x)

sin (\frac{π}{2}) cos (x) = cos (x)

sin (\frac{π}{2}) cos (x)

sin (\frac{π}{2})

بسّط:

1

sin (\frac{π}{2})

استخدم المتطابقة الأساسيّة التالية:

sin (\frac{π}{2}) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1 \cdot cos (x)

1 \cdot cos (x) = cos (x) :

اضرب

= cos (x)

cos (\frac{π}{2}) sin (x) = 0

cos (\frac{π}{2}) sin (x)

cos (\frac{π}{2})

بسّط:

0

cos (\frac{π}{2})

استخدم المتطابقة الأساسيّة التالية:

cos (\frac{π}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= 0 \cdot sin (x)

0 \cdot a = 0

فعّل القانون

= 0

= cos (x) - 0

cos (x) - 0 = cos (x)

= cos (x)

= \frac{cos ( x )}{cos ( \frac{π}{2} ) cos ( x ) + sin ( \frac{π}{2} ) sin ( x )}

cos (\frac{π}{2}) cos (x) + sin (\frac{π}{2}) sin (x) = sin (x)

cos (\frac{π}{2}) cos (x) + sin (\frac{π}{2}) sin (x)

cos (\frac{π}{2}) cos (x) = 0

cos (\frac{π}{2}) cos (x)

cos (\frac{π}{2})

بسّط:

0

cos (\frac{π}{2})

استخدم المتطابقة الأساسيّة التالية:

cos (\frac{π}{2}) = 0

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 0

= 0 \cdot cos (x)

0 \cdot a = 0

فعّل القانون

= 0

sin (\frac{π}{2}) sin (x) = sin (x)

sin (\frac{π}{2}) sin (x)

sin (\frac{π}{2})

بسّط:

1

sin (\frac{π}{2})

استخدم المتطابقة الأساسيّة التالية:

sin (\frac{π}{2}) = 1

sin (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

= 1

= 1 \cdot sin (x)

1 \cdot sin (x) = sin (x) :

اضرب

= sin (x)

= 0 + sin (x)

0 + sin (x) = sin (x)

= sin (x)

= \frac{cos ( x )}{sin ( x )}

= \frac{cos ( x )}{sin ( x )}

\frac{cos ( x )}{sin ( x )} + tan (x) - 1 = 0

\frac{cos ( x )}{sin ( x )} + tan (x) - 1 = 0

\frac{cos ( x )}{sin ( x )} + tan (x) - 1

بسّط:

\frac{cos ( x ) + tan ( x ) sin ( x ) - sin ( x )}{sin ( x )}

\frac{cos ( x )}{sin ( x )} + tan (x) - 1

tan (x) = \frac{tan ( x ) sin ( x )}{sin ( x )}, 1 = \frac{1 sin ( x )}{sin ( x )}

:حوّل الأعداد لكسور

= \frac{cos ( x )}{sin ( x )} + \frac{tan ( x ) sin ( x )}{sin ( x )} - \frac{1 \cdot sin ( x )}{sin ( x )}

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

:بما أنّ المقامات متساوية، اجمع البسوط

= \frac{cos ( x ) + tan ( x ) sin ( x ) - 1 \cdot sin ( x )}{sin ( x )}

1 \cdot sin (x) = sin (x) :

اضرب

= \frac{cos ( x ) + tan ( x ) sin ( x ) - sin ( x )}{sin ( x )}

\frac{cos ( x ) + tan ( x ) sin ( x ) - sin ( x )}{sin ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos (x) + tan (x) sin (x) - sin (x) = 0

sin, cos :

عبّر بواسطة

cos (x) - sin (x) + sin (x) tan (x)

tan (x) = \frac{sin ( x )}{cos ( x )}

:Use the basic trigonometric identity

= cos (x) - sin (x) + sin (x) \frac{sin ( x )}{cos ( x )}

cos (x) - sin (x) + sin (x) \frac{sin ( x )}{cos ( x )}

بسّط:

\frac{cos ^{2} ( x ) - sin ( x ) cos ( x ) + sin ^{2} ( x )}{cos ( x )}

cos (x) - sin (x) + sin (x) \frac{sin ( x )}{cos ( x )}

sin (x) \frac{sin ( x )}{cos ( x )} = \frac{sin ^{2} ( x )}{cos ( x )}

sin (x) \frac{sin ( x )}{cos ( x )}

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

:اضرب كسور

= \frac{sin ( x ) sin ( x )}{cos ( x )}

sin (x) sin (x) = sin^{2} (x)

sin (x) sin (x)

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

sin (x) sin (x) = sin^{1 + 1} (x)

= sin^{1 + 1} (x)

1 + 1 = 2 :

اجمع الأعداد

= sin^{2} (x)

= \frac{sin ^{2} ( x )}{cos ( x )}

= cos (x) - sin (x) + \frac{sin ^{2} ( x )}{cos ( x )}

cos (x) = \frac{cos ( x ) cos ( x )}{cos ( x )}, sin (x) = \frac{sin ( x ) cos ( x )}{cos ( x )}

:حوّل الأعداد لكسور

= \frac{cos ( x ) cos ( x )}{cos ( x )} - \frac{sin ( x ) cos ( x )}{cos ( x )} + \frac{sin ^{2} ( x )}{cos ( x )}

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

:بما أنّ المقامات متساوية، اجمع البسوط

= \frac{cos ( x ) cos ( x ) - sin ( x ) cos ( x ) + sin ^{2} ( x )}{cos ( x )}

cos (x) cos (x) - sin (x) cos (x) + sin^{2} (x) = cos^{2} (x) - sin (x) cos (x) + sin^{2} (x)

cos (x) cos (x) - sin (x) cos (x) + sin^{2} (x)

cos (x) cos (x) = cos^{2} (x)

cos (x) cos (x)

a^{b} \cdot a^{c} = a^{b + c}

:فعّل قانون القوى

cos (x) cos (x) = cos^{1 + 1} (x)

= cos^{1 + 1} (x)

1 + 1 = 2 :

اجمع الأعداد

= cos^{2} (x)

= cos^{2} (x) - sin (x) cos (x) + sin^{2} (x)

= \frac{cos ^{2} ( x ) - sin ( x ) cos ( x ) + sin ^{2} ( x )}{cos ( x )}

= \frac{cos ^{2} ( x ) - sin ( x ) cos ( x ) + sin ^{2} ( x )}{cos ( x )}

\frac{cos ^{2} ( x ) + sin ^{2} ( x ) - cos ( x ) sin ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

cos^{2} (x) + sin^{2} (x) - cos (x) sin (x) = 0

Rewrite using trig identities

- cos (x) sin (x) + 1

2 sin (x) cos (x) = sin (2 x)

:فعّل متطابقة الزاوية المضاعفة

sin (x) cos (x) = \frac{sin ( 2 x )}{2}

= 1 - \frac{sin ( 2 x )}{2}

1 - \frac{sin ( 2 x )}{2} = 0

انقل

1

إلى الجانب الأيمن

1 - \frac{sin ( 2 x )}{2} = 0

من الطرفين

1

اطرح

1 - \frac{sin ( 2 x )}{2} - 1 = 0 - 1

بسّط

- \frac{sin ( 2 x )}{2} = - 1

- \frac{sin ( 2 x )}{2} = - 1

2

اضرب الطرفين بـ

- \frac{sin ( 2 x )}{2} = - 1

2

اضرب الطرفين بـ

2 (- \frac{sin ( 2 x )}{2}) = 2 (- 1)

بسّط

- sin (2 x) = - 2

- sin (2 x) = - 2

- 1

اقسم الطرفين على

- sin (2 x) = - 2

- 1

اقسم الطرفين على

\frac{- sin ( 2 x )}{- 1} = \frac{- 2}{- 1}

بسّط

sin (2 x) = 2

sin (2 x) = 2

- 1 \leq sin (x) \leq 1

x \in R لا يوجد حلّ لـ

رسم

أمثلة شائعة

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