csc(θ)=-2,0<= θ<= 360

Lösung

csc (θ) = - 2, 0^{\circ} \leq θ \leq 36 0^{\circ}

θ = 21 0^{\circ}, θ = 33 0^{\circ}

Radianten

θ = \frac{7 π}{6}, θ = \frac{11 π}{6}

Schritte zur Lösung

csc (θ) = - 2, 0^{\circ} \leq θ \leq 36 0^{\circ}

Allgemeine Lösung für

csc (θ) = - 2

csc (x)

Periodizitätstabelle mit

36 0^{\circ} n

Zyklus:

x 0 3 0^{\circ} 4 5^{\circ} 6 0^{\circ} 9 0^{\circ} 12 0^{\circ} 13 5^{\circ} 15 0^{\circ} csc (x) Undefiend 22 \frac{2 3}{3} 1 \frac{2 3}{3} 22 x 18 0^{\circ} 21 0^{\circ} 22 5^{\circ} 24 0^{\circ} 27 0^{\circ} 30 0^{\circ} 31 5^{\circ} 33 0^{\circ} csc (x) Undefiend - 2 - 2 - \frac{2 3}{3} - 1 - \frac{2 3}{3} - 2 - 2

θ = 21 0^{\circ} + 36 0^{\circ} n, θ = 33 0^{\circ} + 36 0^{\circ} n

θ = 21 0^{\circ} + 36 0^{\circ} n, θ = 33 0^{\circ} + 36 0^{\circ} n

Lösungen für den Bereich

0 \leq θ \leq 36 0^{\circ}

θ = 21 0^{\circ}, θ = 33 0^{\circ}

sin (B) = \frac{12}{13}

csc (x - 4 5^{\circ}) = 2

- 5 sin (2 t) = 0

(cos (x) - 1) = 0

\frac{1}{2} cos^{2} (2 x) + tan (16 2^{\circ}) = 0