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人気のある三角関数 >

400+290cos(x)+290sin(x)=0

解

400 + 290 cos (x) + 290 sin (x) = 0

解

x = - 2.13356 \dots + 2 πn, x = - 2.57882 \dots + 2 πn

+1

度

x = - 122.24412 \dots^{\circ} + 36 0^{\circ} n, x = - 147.75587 \dots^{\circ} + 36 0^{\circ} n

解答ステップ

400 + 290 cos (x) + 290 sin (x) = 0

両辺から

290 sin (x)

を引く

400 + 290 cos (x) = - 290 sin (x)

両辺を2乗する

(400 + 290 cos (x))^{2} = (- 290 sin (x))^{2}

両辺から

(- 290 sin (x))^{2}

を引く

(400 + 290 cos (x))^{2} - 84100 sin^{2} (x) = 0

三角関数の公式を使用して書き換える

(400 + 290 cos (x))^{2} - 84100 sin^{2} (x)

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

sin^{2} (x) = 1 - cos^{2} (x)

= (400 + 290 cos (x))^{2} - 84100 (1 - cos^{2} (x))

簡素化

(400 + 290 cos (x))^{2} - 84100 (1 - cos^{2} (x)) : 168200 cos^{2} (x) + 232000 cos (x) + 75900

(400 + 290 cos (x))^{2} - 84100 (1 - cos^{2} (x))

(400 + 290 cos (x))^{2} : 160000 + 232000 cos (x) + 84100 cos^{2} (x)

完全平方式を適用する:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 400, b = 290 cos (x)

= 40 0^{2} + 2 \cdot 400 \cdot 290 cos (x) + (290 cos (x))^{2}

簡素化

40 0^{2} + 2 \cdot 400 \cdot 290 cos (x) + (290 cos (x))^{2} : 160000 + 232000 cos (x) + 84100 cos^{2} (x)

40 0^{2} + 2 \cdot 400 \cdot 290 cos (x) + (290 cos (x))^{2}

40 0^{2} = 160000

40 0^{2}

40 0^{2} = 160000

= 160000

2 \cdot 400 \cdot 290 cos (x) = 232000 cos (x)

2 \cdot 400 \cdot 290 cos (x)

数を乗じる:

2 \cdot 400 \cdot 290 = 232000

= 232000 cos (x)

(290 cos (x))^{2} = 84100 cos^{2} (x)

(290 cos (x))^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

= 29 0^{2} cos^{2} (x)

29 0^{2} = 84100

= 84100 cos^{2} (x)

= 160000 + 232000 cos (x) + 84100 cos^{2} (x)

= 160000 + 232000 cos (x) + 84100 cos^{2} (x)

= 160000 + 232000 cos (x) + 84100 cos^{2} (x) - 84100 (1 - cos^{2} (x))

拡張

- 84100 (1 - cos^{2} (x)) : - 84100 + 84100 cos^{2} (x)

- 84100 (1 - cos^{2} (x))

分配法則を適用する:

a (b - c) = ab - a c

a = - 84100, b = 1, c = cos^{2} (x)

= - 84100 \cdot 1 - (- 84100) cos^{2} (x)

マイナス・プラスの規則を適用する

- (- a) = a

= - 84100 \cdot 1 + 84100 cos^{2} (x)

数を乗じる:

84100 \cdot 1 = 84100

= - 84100 + 84100 cos^{2} (x)

= 160000 + 232000 cos (x) + 84100 cos^{2} (x) - 84100 + 84100 cos^{2} (x)

簡素化

160000 + 232000 cos (x) + 84100 cos^{2} (x) - 84100 + 84100 cos^{2} (x) : 168200 cos^{2} (x) + 232000 cos (x) + 75900

160000 + 232000 cos (x) + 84100 cos^{2} (x) - 84100 + 84100 cos^{2} (x)

条件のようなグループ

= 232000 cos (x) + 84100 cos^{2} (x) + 84100 cos^{2} (x) + 160000 - 84100

類似した元を足す:

84100 cos^{2} (x) + 84100 cos^{2} (x) = 168200 cos^{2} (x)

= 232000 cos (x) + 168200 cos^{2} (x) + 160000 - 84100

数を足す/引く:

160000 - 84100 = 75900

= 168200 cos^{2} (x) + 232000 cos (x) + 75900

= 168200 cos^{2} (x) + 232000 cos (x) + 75900

= 168200 cos^{2} (x) + 232000 cos (x) + 75900

75900 + 168200 cos^{2} (x) + 232000 cos (x) = 0

置換で解く

75900 + 168200 cos^{2} (x) + 232000 cos (x) = 0

仮定:

cos (x) = u

75900 + 168200 u^{2} + 232000 u = 0

75900 + 168200 u^{2} + 232000 u = 0 : u = \frac{- 40 + 82}{58}, u = \frac{- 40 - 82}{58}

75900 + 168200 u^{2} + 232000 u = 0

以下で両辺を割る

168200

\frac{75900}{168200} + \frac{168200 u ^{2}}{168200} + \frac{232000 u}{168200} = \frac{0}{168200}

標準的な形式で書く

a x^{2} + b x + c = 0

u^{2} + \frac{40 u}{29} + \frac{759}{1682} = 0

解くとthe二次式

u^{2} + \frac{40 u}{29} + \frac{759}{1682} = 0

二次Equationの公式:

次の場合:

a = 1, b = \frac{40}{29}, c = \frac{759}{1682}

u_{1, 2} = \frac{- \frac{40}{29} \pm ( \frac{40}{29} ) ^{2} - 4 \cdot 1 \cdot \frac{759}{1682}}{2 \cdot 1}

u_{1, 2} = \frac{- \frac{40}{29} \pm ( \frac{40}{29} ) ^{2} - 4 \cdot 1 \cdot \frac{759}{1682}}{2 \cdot 1}

(\frac{40}{29})^{2} - 4 \cdot 1 \cdot \frac{759}{1682} = \frac{82}{29}

(\frac{40}{29})^{2} - 4 \cdot 1 \cdot \frac{759}{1682}

(\frac{40}{29})^{2} = \frac{4 0 ^{2}}{2 9 ^{2}}

(\frac{40}{29})^{2}

指数の規則を適用する:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{4 0 ^{2}}{2 9 ^{2}}

4 \cdot 1 \cdot \frac{759}{1682} = \frac{1518}{841}

4 \cdot 1 \cdot \frac{759}{1682}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 1 \cdot \frac{759 \cdot 4}{1682}

\frac{759 \cdot 4}{1682} = \frac{1518}{841}

\frac{759 \cdot 4}{1682}

数を乗じる:

759 \cdot 4 = 3036

= \frac{3036}{1682}

共通因数を約分する:

2

= \frac{1518}{841}

= 1 \cdot \frac{1518}{841}

乗算:

1 \cdot \frac{1518}{841} = \frac{1518}{841}

= \frac{1518}{841}

= \frac{4 0 ^{2}}{2 9 ^{2}} - \frac{1518}{841}

\frac{4 0 ^{2}}{2 9 ^{2}} = \frac{1600}{841}

\frac{4 0 ^{2}}{2 9 ^{2}}

4 0^{2} = 1600

= \frac{1600}{2 9 ^{2}}

2 9^{2} = 841

= \frac{1600}{841}

= \frac{1600}{841} - \frac{1518}{841}

分数を組み合わせる

\frac{1600}{841} - \frac{1518}{841} : \frac{82}{841}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{1600 - 1518}{841}

数を引く:

1600 - 1518 = 82

= \frac{82}{841}

= \frac{82}{841}

累乗根の規則を適用する:

n \frac{a}{b} = \frac{n a}{n b},

, 以下を想定

a \geq 0, b \geq 0

= \frac{82}{841}

841 = 29

841

数を因数に分解する:

841 = 2 9^{2}

= 2 9^{2}

累乗根の規則を適用する:

n a^{n} = a

2 9^{2} = 29

= 29

= \frac{82}{29}

u_{1, 2} = \frac{- \frac{40}{29} \pm \frac{82}{29}}{2 \cdot 1}

解を分離する

u_{1} = \frac{- \frac{40}{29} + \frac{82}{29}}{2 \cdot 1}, u_{2} = \frac{- \frac{40}{29} - \frac{82}{29}}{2 \cdot 1}

u = \frac{- \frac{40}{29} + \frac{82}{29}}{2 \cdot 1} : \frac{- 40 + 82}{58}

\frac{- \frac{40}{29} + \frac{82}{29}}{2 \cdot 1}

分数を組み合わせる

- \frac{40}{29} + \frac{82}{29} : \frac{- 40 + 82}{29}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 40 + 82}{29}

= \frac{\frac{- 40 + 82}{29}}{2 \cdot 1}

数を乗じる:

2 \cdot 1 = 2

= \frac{\frac{- 40 + 82}{29}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 40 + 82}{29 \cdot 2}

数を乗じる:

29 \cdot 2 = 58

= \frac{- 40 + 82}{58}

u = \frac{- \frac{40}{29} - \frac{82}{29}}{2 \cdot 1} : \frac{- 40 - 82}{58}

\frac{- \frac{40}{29} - \frac{82}{29}}{2 \cdot 1}

分数を組み合わせる

- \frac{40}{29} - \frac{82}{29} : \frac{- 40 - 82}{29}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 40 - 82}{29}

= \frac{\frac{- 40 - 82}{29}}{2 \cdot 1}

数を乗じる:

2 \cdot 1 = 2

= \frac{\frac{- 40 - 82}{29}}{2}

分数の規則を適用する:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{- 40 - 82}{29 \cdot 2}

数を乗じる:

29 \cdot 2 = 58

= \frac{- 40 - 82}{58}

二次equationの解:

u = \frac{- 40 + 82}{58}, u = \frac{- 40 - 82}{58}

代用を戻す

u = cos (x)

cos (x) = \frac{- 40 + 82}{58}, cos (x) = \frac{- 40 - 82}{58}

cos (x) = \frac{- 40 + 82}{58}, cos (x) = \frac{- 40 - 82}{58}

cos (x) = \frac{- 40 + 82}{58} : x = arccos (\frac{- 40 + 82}{58}) + 2 πn, x = - arccos (\frac{- 40 + 82}{58}) + 2 πn

cos (x) = \frac{- 40 + 82}{58}

三角関数の逆数プロパティを適用する

cos (x) = \frac{- 40 + 82}{58}

以下の一般解

cos (x) = \frac{- 40 + 82}{58}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (\frac{- 40 + 82}{58}) + 2 πn, x = - arccos (\frac{- 40 + 82}{58}) + 2 πn

x = arccos (\frac{- 40 + 82}{58}) + 2 πn, x = - arccos (\frac{- 40 + 82}{58}) + 2 πn

cos (x) = \frac{- 40 - 82}{58} : x = arccos (\frac{- 40 - 82}{58}) + 2 πn, x = - arccos (\frac{- 40 - 82}{58}) + 2 πn

cos (x) = \frac{- 40 - 82}{58}

三角関数の逆数プロパティを適用する

cos (x) = \frac{- 40 - 82}{58}

以下の一般解

cos (x) = \frac{- 40 - 82}{58}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

x = arccos (\frac{- 40 - 82}{58}) + 2 πn, x = - arccos (\frac{- 40 - 82}{58}) + 2 πn

x = arccos (\frac{- 40 - 82}{58}) + 2 πn, x = - arccos (\frac{- 40 - 82}{58}) + 2 πn

すべての解を組み合わせる

x = arccos (\frac{- 40 + 82}{58}) + 2 πn, x = - arccos (\frac{- 40 + 82}{58}) + 2 πn, x = arccos (\frac{- 40 - 82}{58}) + 2 πn, x = - arccos (\frac{- 40 - 82}{58}) + 2 πn

元のequationに当てはめて解を検算する

400 + 290 cos (x) + 290 sin (x) = 0

に当てはめて解を確認する

equationに一致しないものを削除する。

解答を確認する

arccos (\frac{- 40 + 82}{58}) + 2 πn :

偽

arccos (\frac{- 40 + 82}{58}) + 2 πn

挿入

n = 1

arccos (\frac{- 40 + 82}{58}) + 2 π 1

400 + 290 cos (x) + 290 sin (x) = 0

の挿入向け

x = arccos (\frac{- 40 + 82}{58}) + 2 π 1

400 + 290 cos (arccos (\frac{- 40 + 82}{58}) + 2 π 1) + 290 sin (arccos (\frac{- 40 + 82}{58}) + 2 π 1) = 0

改良

490.55385 \dots = 0

\Rightarrow 偽

解答を確認する

- arccos (\frac{- 40 + 82}{58}) + 2 πn :

真

- arccos (\frac{- 40 + 82}{58}) + 2 πn

挿入

n = 1

- arccos (\frac{- 40 + 82}{58}) + 2 π 1

400 + 290 cos (x) + 290 sin (x) = 0

の挿入向け

x = - arccos (\frac{- 40 + 82}{58}) + 2 π 1

400 + 290 cos (- arccos (\frac{- 40 + 82}{58}) + 2 π 1) + 290 sin (- arccos (\frac{- 40 + 82}{58}) + 2 π 1) = 0

改良

0 = 0

\Rightarrow 真

解答を確認する

arccos (\frac{- 40 - 82}{58}) + 2 πn :

偽

arccos (\frac{- 40 - 82}{58}) + 2 πn

挿入

n = 1

arccos (\frac{- 40 - 82}{58}) + 2 π 1

400 + 290 cos (x) + 290 sin (x) = 0

の挿入向け

x = arccos (\frac{- 40 - 82}{58}) + 2 π 1

400 + 290 cos (arccos (\frac{- 40 - 82}{58}) + 2 π 1) + 290 sin (arccos (\frac{- 40 - 82}{58}) + 2 π 1) = 0

改良

309.44614 \dots = 0

\Rightarrow 偽

解答を確認する

- arccos (\frac{- 40 - 82}{58}) + 2 πn :

真

- arccos (\frac{- 40 - 82}{58}) + 2 πn

挿入

n = 1

- arccos (\frac{- 40 - 82}{58}) + 2 π 1

400 + 290 cos (x) + 290 sin (x) = 0

の挿入向け

x = - arccos (\frac{- 40 - 82}{58}) + 2 π 1

400 + 290 cos (- arccos (\frac{- 40 - 82}{58}) + 2 π 1) + 290 sin (- arccos (\frac{- 40 - 82}{58}) + 2 π 1) = 0

改良

0 = 0

\Rightarrow 真

x = - arccos (\frac{- 40 + 82}{58}) + 2 πn, x = - arccos (\frac{- 40 - 82}{58}) + 2 πn

10進法形式で解を証明する

x = - 2.13356 \dots + 2 πn, x = - 2.57882 \dots + 2 πn

グラフ

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