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受欢迎的三角函数 >

tan(25)=cot(2x+5)

解答

tan (2 5^{\circ}) = cot (2 x + 5)

解答

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

+1

弧度

x = - \frac{5}{2} + \frac{13 π}{72} + \frac{π}{2} n

求解步骤

tan (2 5^{\circ}) = cot (2 x + 5)

交换两边

cot (2 x + 5) = tan (2 5^{\circ})

使用反三角函数性质

cot (2 x + 5) = tan (2 5^{\circ})

cot (2 x + 5) = tan (2 5^{\circ})

的通解

cot (x) = a \Rightarrow x = arccot (a) + 18 0^{\circ} n

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n

解

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n : x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

2 x + 5 = arccot (tan (2 5^{\circ})) + 18 0^{\circ} n

化简

arccot (tan (2 5^{\circ})) + 18 0^{\circ} n : 6 5^{\circ} + 18 0^{\circ} n

arccot (tan (2 5^{\circ})) + 18 0^{\circ} n

arccot (tan (2 5^{\circ})) = 6 5^{\circ}

arccot (tan (2 5^{\circ}))

使用三角恒等式改写:

tan (2 5^{\circ}) = cot (6 5^{\circ})

tan (2 5^{\circ})

cot (9 0^{\circ} - x) = tan (x)

= cot (9 0^{\circ} - 2 5^{\circ})

= cot (6 5^{\circ})

= arccot (cot (6 5^{\circ}))

Use the inverse trig property:

6 5^{\circ}

arccot (cot (6 5^{\circ}))

对于

0 < x < 18 0^{\circ}, a rcco t (co t (x)) = x

0 < 6 5^{\circ} < 18 0^{\circ}

= 6 5^{\circ}

= 6 5^{\circ}

= 6 5^{\circ} + 18 0^{\circ} n

2 x + 5 = 6 5^{\circ} + 18 0^{\circ} n

将

5

到右边

2 x + 5 = 6 5^{\circ} + 18 0^{\circ} n

两边减去

5

2 x + 5 - 5 = 6 5^{\circ} + 18 0^{\circ} n - 5

化简

2 x = 6 5^{\circ} + 18 0^{\circ} n - 5

2 x = 6 5^{\circ} + 18 0^{\circ} n - 5

两边除以

2

2 x = 6 5^{\circ} + 18 0^{\circ} n - 5

两边除以

2

\frac{2 x}{2} = \frac{6 5 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{5}{2}

化简

\frac{2 x}{2} = \frac{6 5 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{5}{2}

化简

\frac{2 x}{2} : x

\frac{2 x}{2}

数字相除:

\frac{2}{2} = 1

= x

化简

\frac{6 5 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{5}{2} : - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

\frac{6 5 ^{\circ}}{2} + \frac{18 0 ^{\circ} n}{2} - \frac{5}{2}

对同类项分组

= - \frac{5}{2} + \frac{18 0 ^{\circ} n}{2} + \frac{6 5 ^{\circ}}{2}

\frac{6 5 ^{\circ}}{2} = 32. 5^{\circ}

\frac{6 5 ^{\circ}}{2}

使用分式法则:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{234 0 ^{\circ}}{36 \cdot 2}

数字相乘:

36 \cdot 2 = 72

= 32. 5^{\circ}

= - \frac{5}{2} + \frac{18 0 ^{\circ} n}{2} + 32. 5^{\circ}

对同类项分组

= - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

x = - \frac{5}{2} + 32. 5^{\circ} + \frac{18 0 ^{\circ} n}{2}

作图

流行的例子

sin (a) = 0.4

sin (a) = 0.2

sin(2x)=1.47(sin(x))^2

sin (2 x) = 1.47 (sin (x))^{2}

2 sin^{2} (u) = 1 +, u

8.5 = 12 sin (a)