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受欢迎的三角函数 >

solvefor x,r+s+6t=cos(2x+y)

解答

求解

x, r + s + 6 t = cos (2 x + y)

解答

x = \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}, x = - \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

求解步骤

r + s + 6 t = cos (2 x + y)

交换两边

cos (2 x + y) = r + s + 6 t

使用反三角函数性质

cos (2 x + y) = r + s + 6 t

cos (2 x + y) = r + s + 6 t

的通解

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

2 x + y = arccos (r + s + 6 t) + 2 πn, 2 x + y = - arccos (r + s + 6 t) + 2 πn

2 x + y = arccos (r + s + 6 t) + 2 πn, 2 x + y = - arccos (r + s + 6 t) + 2 πn

解

2 x + y = arccos (r + s + 6 t) + 2 πn : x = \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

2 x + y = arccos (r + s + 6 t) + 2 πn

将

y

到右边

2 x + y = arccos (r + s + 6 t) + 2 πn

两边减去

y

2 x + y - y = arccos (r + s + 6 t) + 2 πn - y

化简

2 x = arccos (r + s + 6 t) + 2 πn - y

2 x = arccos (r + s + 6 t) + 2 πn - y

两边除以

2

2 x = arccos (r + s + 6 t) + 2 πn - y

两边除以

2

\frac{2 x}{2} = \frac{arccos ( r + s + 6 t )}{2} + \frac{2 πn}{2} - \frac{y}{2}

化简

x = \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

x = \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

解

2 x + y = - arccos (r + s + 6 t) + 2 πn : x = - \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

2 x + y = - arccos (r + s + 6 t) + 2 πn

将

y

到右边

2 x + y = - arccos (r + s + 6 t) + 2 πn

两边减去

y

2 x + y - y = - arccos (r + s + 6 t) + 2 πn - y

化简

2 x = - arccos (r + s + 6 t) + 2 πn - y

2 x = - arccos (r + s + 6 t) + 2 πn - y

两边除以

2

2 x = - arccos (r + s + 6 t) + 2 πn - y

两边除以

2

\frac{2 x}{2} = - \frac{arccos ( r + s + 6 t )}{2} + \frac{2 πn}{2} - \frac{y}{2}

化简

x = - \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

x = - \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

x = \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}, x = - \frac{arccos ( r + s + 6 t )}{2} + πn - \frac{y}{2}

作图

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