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受欢迎的三角函数 >

cos(8x)=1

解答

cos (8 x) = 1

解答

x = \frac{πn}{4}

+1

度数

x = 0^{\circ} + 4 5^{\circ} n

求解步骤

cos (8 x) = 1

cos (8 x) = 1

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

8 x = 0 + 2 πn

8 x = 0 + 2 πn

解

8 x = 0 + 2 πn : x = \frac{πn}{4}

8 x = 0 + 2 πn

0 + 2 πn = 2 πn

8 x = 2 πn

两边除以

8

8 x = 2 πn

两边除以

8

\frac{8 x}{8} = \frac{2 πn}{8}

化简

x = \frac{πn}{4}

x = \frac{πn}{4}

x = \frac{πn}{4}

作图

流行的例子

cos^4(a)=8cos^4(a)-8cos^2(a)+1

cos^{4} (a) = 8 cos^{4} (a) - 8 cos^{2} (a) + 1

sin^2(a)-4sin(a)+3=0

sin^{2} (a) - 4 sin (a) + 3 = 0

4sin^2(x)-4cos(x)-1=0

4 sin^{2} (x) - 4 cos (x) - 1 = 0

3cos^2(x)+2cos(x)-8=0

3 cos^{2} (x) + 2 cos (x) - 8 = 0

tan(a)+sec(a)= 3/2

tan (a) + sec (a) = \frac{3}{2}