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受欢迎的三角函数 >

tan^5(x)tan^2(x)=1

解答

tan^{5} (x) tan^{2} (x) = 1

解答

x = \frac{π}{4} + πn

+1

度数

x = 4 5^{\circ} + 18 0^{\circ} n

求解步骤

tan^{5} (x) tan^{2} (x) = 1

化简

tan^{5} (x) tan^{2} (x) : tan^{7} (x)

tan^{5} (x) tan^{2} (x)

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

tan^{5} (x) tan^{2} (x) = tan^{5 + 2} (x)

= tan^{5 + 2} (x)

数字相加:

5 + 2 = 7

= tan^{7} (x)

tan^{7} (x) = 1

对于

x^{n} = f (a)

，n 为奇数，解为

x = n f (a)

tan (x) = 71

71 = 1

71

使用法则

n 1 = 1

= 1

tan (x) = 1

tan (x) = 1

的通解

tan (x)

周期表（周期为

πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} tan (x) 0 \frac{3}{3} 13 \pm \infty - 3 - 1 - \frac{3}{3}

x = \frac{π}{4} + πn

x = \frac{π}{4} + πn

作图

流行的例子

(sin^2(a)+1)/((1+tan^2(a)))=1

\frac{sin ^{2} ( a ) + 1}{( 1 + tan ^{2} ( a ) )} = 1

tan(a)= 5/9 ,b=6

tan (a) = \frac{5}{9}, b = 6

sin^3(x)sin^2(x)sin(x)=0

sin^{3} (x) sin^{2} (x) sin (x) = 0

2cos^2(x)+1=cos^2(x)

2 cos^{2} (x) + 1 = cos^{2} (x)

sin^2(x)cos^2(x)=((1-cos^4(x)))/8

sin^{2} (x) cos^{2} (x) = \frac{( 1 - cos ^{4} ( x ) )}{8}