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Beliebt Word Problems >

Ian is going to invest in an account paying an interest rate of 6.2% compounded continuously. How much would Ian need to invest, to the nearest ten dollars, for the value of the account to reach 182,000 in 10 years?

Lösung

I an i s g o in g t o in v es t in an a cco u n t p a y in g an in t eres t r a t e o f 6.2% co m p o u n d e d co n t in u o u s l y . Ho w m u c h w o u l d I an n ee d t o in v es t, t o t h e n e a res t t e n d o ll a rs, f or t h e v a l u e o f t h e a cco u n t t o re a c h 182, 000 in 10 ye a rs ?

Lösung

Principal : 97905.89

Schritte zur Lösung

Translate the problem into an equation:

182000 = P e^{0.062 \cdot 10}

Löse nach

P, 182000 = P e^{0.062 \cdot 10} : P = 97905.89

Principal : 97905.89

Beliebte Beispiele

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