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Popolare Word Problems >

Find three consecutive odd integers such that three times the product of the first and last integers, decreased by 150, is equal to the square of the second integer.

Soluzione

F in d t h ree co n sec u t i v e o dd in t e g ers s u c h t ha t t h ree t im es t h e p ro d u c t o f t h e f i rs t an d l a s t in t e g ers, d ecre a se d b y 150, i s e q u a l t o t h e s q u a re o f t h e seco n d in t e g er .

Soluzione

Nessuna soluzione

Fasi della soluzione

Represent the numbers with

x

:

First number : x

Consecutive number 1 : x + 2

Consecutive number 2 : x + 4

A.T.Q.:

3 \dots - 150 = (x + 2)^{2}

Risolvi

3 \dots - 150 = (x + 2)^{2} : x = 3 \dots - 150 - 2, x = - 3 \dots - 150 - 2

Inserire in

x = 3 \dots - 150 - 2 :

Non valido

Inserire in

x = - 3 \dots - 150 - 2 :

Non valido

Nessuna soluzione

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