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The sum of the reciprocals of 2 consecutive integers is 23/132 . Find the numbers

Solução

The sum of the reciprocals of 2 consecutive integers is 23/132 . Find the numbers

Solução

The numbers : 11, 12 or - \frac{12}{23}, \frac{11}{23}

Passos da solução

Represent the numbers with

x

:

First number : x

Consecutive number : x + 1

A.T.Q.:

\frac{1}{x} + \frac{1}{x + 1} = \frac{23}{132}

Resolver

\frac{1}{x} + \frac{1}{x + 1} = \frac{23}{132} : x = 11, x = - \frac{12}{23}

Inserir

x = 11 : 12

Inserir

x = - \frac{12}{23} : \frac{11}{23}

The numbers : 11, 12 or - \frac{12}{23}, \frac{11}{23}

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