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(\partial)/(\partial x)(ln(x^{12}-y^8))

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∂ ∂ x (ln(x¹²−y⁸))

Solution

12x¹¹x¹²−y⁸

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∂ ∂ x (ln(x¹²−y⁸))

Treat y as a constant

Apply the chain rule: 1x¹²−y⁸ ∂ ∂ x (x¹²−y⁸)

=1x¹²−y⁸ ∂ ∂ x (x¹²−y⁸)

∂ ∂ x (x¹²−y⁸)=12x¹¹

=1x¹²−y⁸ · 12x¹¹

Simplify 1x¹²−y⁸ · 12x¹¹: 12x¹¹x¹²−y⁸

=12x¹¹x¹²−y⁸

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(\partial)/(\partial x)(ln(x^{12}-y^8))

Solution

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