faktorisieren-27x^3+64

Lösung

faktorisieren

- 27 x^{3} + 64

- (3 x - 4) (9 x^{2} + 12 x + 16)

Schritte zur Lösung

- 27 x^{3} + 64

Klammere aus

- 1 : - (27 x^{3} - 64)

= - (27 x^{3} - 64)

Faktorisiere

27 x^{3} - 64 : (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2})

= - (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2})

Vereinfache

- (3 x - 4) (3^{2} x^{2} + 4 \cdot 3 x + 4^{2}) : - (3 x - 4) (9 x^{2} + 12 x + 16)

= - (3 x - 4) (9 x^{2} + 12 x + 16)

\frac{2 - x}{3} + 30 = 24

x^{2} = 2 - x

f a c t or 4 x^{4} - 64 x^{2}

26 + 9 p = 58 p

3 x^{2} + 5 x - 2 \geq 0