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Frequently Asked Questions (FAQ)
What are the solutions to the equation 199-2x^2=x^2+33x+28 ?
- The solutions to the equation 199-2x^2=x^2+33x+28 are x=(-11+sqrt(349))/2 ,x=-(11+sqrt(349))/2
Find the zeros of 199-2x^2=x^2+33x+28
- The zeros of 199-2x^2=x^2+33x+28 are x=(-11+sqrt(349))/2 ,x=-(11+sqrt(349))/2