(x-1)(x+2)-(2x-3)(x+4)-x+14=0

Lösung

(x - 1) (x + 2) - (2 x - 3) (x + 4) - x + 14 = 0

x = - 8, x = 3

Schritte zur Lösung

(x - 1) (x + 2) - (2 x - 3) (x + 4) - x + 14 = 0

Schreibe

(x - 1) (x + 2) - (2 x - 3) (x + 4) - x + 14

um:

- x^{2} - 5 x + 24

- x^{2} - 5 x + 24 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 24}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 24 = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 ( - 1 )}

Trenne die Lösungen

x_{1} = \frac{- ( - 5 ) + 11}{2 ( - 1 )}, x_{2} = \frac{- ( - 5 ) - 11}{2 ( - 1 )}

x = \frac{- ( - 5 ) + 11}{2 ( - 1 )} : - 8

x = \frac{- ( - 5 ) - 11}{2 ( - 1 )} : 3

Die Lösungen für die quadratische Gleichung sind:

x = - 8, x = 3

(2 x + 3)^{2} + 5 = 8

x^{2} + x = 3

(x + 5) (x + 2) = 0

3 x^{2} + 7 = 301

x^{2} + 7 x = 68.75