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受欢迎的代数 >

(8x^2-15x)-(x^2-27x)=ax^2+bx

解答

(8 x^{2} - 15 x) - (x^{2} - 27 x) = a x^{2} + b x

解答

x = 0, x = \frac{b - 12}{7 - a}; a \neq = 7

求解步骤

(8 x^{2} - 15 x) - (x^{2} - 27 x) = a x^{2} + b x

展开

(8 x^{2} - 15 x) - (x^{2} - 27 x) : 7 x^{2} + 12 x

7 x^{2} + 12 x = a x^{2} + b x

将

b x

para o lado esquerdo

7 x^{2} + 12 x - b x = a x^{2}

将

a x^{2}

para o lado esquerdo

7 x^{2} + 12 x - b x - a x^{2} = 0

因式分解

7 x^{2} + 12 x - b x - a x^{2} : x (7 x - b - a x + 12)

x (7 x - b - a x + 12) = 0

使用零因数法则： If

ab = 0

then

a = 0

or

b = 0

x = 0 or 7 x - b - a x + 12 = 0

解

7 x - b - a x + 12 = 0 : x = \frac{b - 12}{7 - a}; a \neq = 7

二次方程组的解是:

x = 0, x = \frac{b - 12}{7 - a}; a \neq = 7

作图

流行的例子

3 x^{2} - 6 = x^{2} + 2

- 2 x^{2} - 3 x + 1 = 0

solvefor x,x^2+y^2=4

so l v e f or x, x^{2} + y^{2} = 4

因式分解 2x^2+7x+6=0

f a c t or 2 x^{2} + 7 x + 6 = 0

completesquare x^2-2x-1

co m pl e t es q u a re x^{2} - 2 x - 1