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受欢迎的代数 >

k(x)=-x^2-3,k(1)

解答

k (x) = - x^{2} - 3, k (1)

解答

x = - \frac{k + k ^{2} - 12}{2}, x = - \frac{k - k ^{2} - 12}{2}

求解步骤

k (x) = - x^{2} - 3

整理后得

k x = - x^{2} - 3

交换两边

- x^{2} - 3 = k x

将

k x

para o lado esquerdo

- x^{2} - 3 - k x = 0

改写成标准形式

a x^{2} + b x + c = 0

- x^{2} - k x - 3 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - k ) \pm ( - k ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

化简

(- k)^{2} - 4 (- 1) (- 3) : k^{2} - 12

x_{1, 2} = \frac{- ( - k ) \pm k ^{2} - 12}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- ( - k ) + k ^{2} - 12}{2 ( - 1 )}, x_{2} = \frac{- ( - k ) - k ^{2} - 12}{2 ( - 1 )}

x = \frac{- ( - k ) + k ^{2} - 12}{2 ( - 1 )} : - \frac{k + k ^{2} - 12}{2}

x = \frac{- ( - k ) - k ^{2} - 12}{2 ( - 1 )} : - \frac{k - k ^{2} - 12}{2}

二次方程组的解是:

x = - \frac{k + k ^{2} - 12}{2}, x = - \frac{k - k ^{2} - 12}{2}

作图

流行的例子

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\frac{x ^{2}}{4} - \frac{9}{16} = 0

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