化简 (x^2+2x-3)/(x^2-9)*(x-3)/(x^2-4x+3)

解答

化简

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

\frac{1}{x - 3}

求解步骤

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

消掉

\frac{x ^{2} + 2 x - 3}{x ^{2} - 9} : \frac{x - 1}{x - 3}

= \frac{x - 1}{x - 3} \cdot \frac{x - 3}{x ^{2} - 4 x + 3}

交叉约去公约数:

x - 3

= \frac{x - 1}{x ^{2} - 4 x + 3}

因式分解

x^{2} - 4 x + 3 : (x - 1) (x - 3)

= \frac{x - 1}{( x - 1 ) ( x - 3 )}

约分:

x - 1

= \frac{1}{x - 3}

s im pl i f y (\frac{5 a ^{2} b ^{- 8} c}{25 a b ^{0} c ^{6}})^{3}

f a c t or 4 x - 3 x^{2}

s im pl i f y 490 y^{5} w^{6}

s im pl i f y \frac{5}{6} \cdot \frac{4}{15} - \frac{3}{5} \cdot \frac{20}{18}

e x p an d (2 n + 3)^{3}