What is factor+n^4-9n^2+4n^3-36n-12n^2+108 ?

The solution to factor+n^4-9n^2+4n^3-36n-12n^2+108 is (n-2)(n+6)(n+3)(n-3)

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factor+n^4-9n^2+4n^3-36n-12n^2+108

factor

+ n^{4} - 9 n^{2} + 4 n^{3} - 36 n - 12 n^{2} + 108

(n - 2) (n + 6) (n + 3) (n - 3)

Solution steps

n^{4} - 9 n^{2} + 4 n^{3} - 36 n - 12 n^{2} + 108

Add similar elements:

- 9 n^{2} - 12 n^{2} = - 21 n^{2}

= n^{4} - 21 n^{2} + 4 n^{3} - 36 n + 108

Write in the standard form

= n^{4} + 4 n^{3} - 21 n^{2} - 36 n + 108

Use the rational root theorem

= (n - 2) \frac{n ^{4} + 4 n ^{3} - 21 n ^{2} - 36 n + 108}{n - 2}

\frac{n ^{4} + 4 n ^{3} - 21 n ^{2} - 36 n + 108}{n - 2} = n^{3} + 6 n^{2} - 9 n - 54

= (n - 2) (n^{3} + 6 n^{2} - 9 n - 54)

Factor

n^{3} + 6 n^{2} - 9 n - 54 : (n + 6) (n + 3) (n - 3)

= (n - 2) (n + 6) (n + 3) (n - 3)

4 (2 x - 2)^{2} - (2 x - 5) (3 x + 3)

\frac{2}{42}

3.14 \cdot 1 6^{2}

\frac{16 x ^{8} - 625 y ^{4}}{2 x ^{2} + 5 y}

\frac{7}{m} \cdot \frac{m + 7}{14}

What is factor+n^4-9n^2+4n^3-36n-12n^2+108 ?
The solution to factor+n^4-9n^2+4n^3-36n-12n^2+108 is (n-2)(n+6)(n+3)(n-3)