log_{2}(|x|)=4

Lösung

lo g_{2} (∣ x ∣) = 4

x = - 16, x = 16

Schritte zur Lösung

lo g_{2} (∣ x ∣) = 4

Wende die log Regel an

∣ x ∣ = 16

Löse

∣ x ∣ = 16 : x = - 16 or x = 16

x = - 16, x = 16

(x + 2) + (x - 1) = 0

2.25 x = x^{2} - 25

x + 2 \leq \frac{1}{x + 2}

- 7200 (1 + x)^{2} + 5300 (1 + x) + 8000 = 0

f a c t or 27 a^{3} - b^{6}