簡約 ln(5)e^{-(6^2)/2}

解

簡約

ln (5) e^{- \frac{6 ^{2}}{2}}

\frac{ln ( 5 )}{e ^{18}}

十進法表記

2.45117 E - 8

解答ステップ

ln (5) e^{- \frac{6 ^{2}}{2}}

指数の規則を適用する:

a^{- b} = \frac{1}{a ^{b}}

= \frac{1}{e ^{\frac{6 ^{2}}{2}}} ln (5)

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot ln ( 5 )}{e ^{\frac{6 ^{2}}{2}}}

乗算:

1 \cdot ln (5) = ln (5)

= \frac{ln ( 5 )}{e ^{\frac{6 ^{2}}{2}}}

e^{\frac{6 ^{2}}{2}} = e^{3^{2} \cdot 2}

= \frac{ln ( 5 )}{e ^{3^{2} \cdot 2}}

e^{3^{2} \cdot 2} = e^{18}

= \frac{ln ( 5 )}{e ^{18}}