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受欢迎的代数 >

0=75+28925t-5t^2

解答

0 = 75 + 28925 \cdot t - 5 \cdot t^{2}

解答

t = - \frac{- 28925 + 836657125}{10}, t = \frac{28925 + 836657125}{10}

+1

十进制

t = - 0.00259 \dots, t = 5785.00259 \dots

求解步骤

0 = 75 + 28925 t - 5 t^{2}

交换两边

75 + 28925 t - 5 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- 5 t^{2} + 28925 t + 75 = 0

使用求根公式求解

t_{1, 2} = \frac{- 28925 \pm 2892 5 ^{2} - 4 ( - 5 ) \cdot 75}{2 ( - 5 )}

2892 5^{2} - 4 (- 5) \cdot 75 = 836657125

t_{1, 2} = \frac{- 28925 \pm 836657125}{2 ( - 5 )}

将解分隔开

t_{1} = \frac{- 28925 + 836657125}{2 ( - 5 )}, t_{2} = \frac{- 28925 - 836657125}{2 ( - 5 )}

t = \frac{- 28925 + 836657125}{2 ( - 5 )} : - \frac{- 28925 + 836657125}{10}

t = \frac{- 28925 - 836657125}{2 ( - 5 )} : \frac{28925 + 836657125}{10}

二次方程组的解是:

t = - \frac{- 28925 + 836657125}{10}, t = \frac{28925 + 836657125}{10}

作图

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