-5(x)^2-5x+200=0

解

- 5 (x)^{2} - 5 x + 200 = 0

x = - \frac{1 + 161}{2}, x = \frac{161 - 1}{2}

十進法表記

x = - 6.84428 \dots, x = 5.84428 \dots

解答ステップ

- 5 x^{2} - 5 x + 200 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 5 ) \cdot 200}{2 ( - 5 )}

(- 5)^{2} - 4 (- 5) \cdot 200 = 5161

x_{1, 2} = \frac{- ( - 5 ) \pm 5 161}{2 ( - 5 )}

解を分離する

x_{1} = \frac{- ( - 5 ) + 5 161}{2 ( - 5 )}, x_{2} = \frac{- ( - 5 ) - 5 161}{2 ( - 5 )}

x = \frac{- ( - 5 ) + 5 161}{2 ( - 5 )} : - \frac{1 + 161}{2}

x = \frac{- ( - 5 ) - 5 161}{2 ( - 5 )} : \frac{161 - 1}{2}

二次equationの解:

x = - \frac{1 + 161}{2}, x = \frac{161 - 1}{2}