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受欢迎的代数 >

ax^2-2x+4=0

解答

a x^{2} - 2 x + 4 = 0

解答

x = \frac{1 + - 4 a + 1}{a}, x = \frac{1 - - 4 a + 1}{a}; a \neq = 0

求解步骤

a x^{2} - 2 x + 4 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 a \cdot 4}{2 a}

化简

(- 2)^{2} - 4 a \cdot 4 : 2 1 - 4 a

x_{1, 2} = \frac{- ( - 2 ) \pm 2 1 - 4 a}{2 a}; a \neq = 0

将解分隔开

x_{1} = \frac{- ( - 2 ) + 2 1 - 4 a}{2 a}, x_{2} = \frac{- ( - 2 ) - 2 1 - 4 a}{2 a}

x = \frac{- ( - 2 ) + 2 1 - 4 a}{2 a} : \frac{1 + - 4 a + 1}{a}

x = \frac{- ( - 2 ) - 2 1 - 4 a}{2 a} : \frac{1 - - 4 a + 1}{a}

二次方程组的解是:

x = \frac{1 + - 4 a + 1}{a}, x = \frac{1 - - 4 a + 1}{a}; a \neq = 0

作图

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