L^{-1}=[ s/(s^2+2s-3)]

解

L^{- 1} = [\frac{s}{s ^{2} + 2 s - 3}]

s = \frac{- 2 + L + L ^{2} - 4 L + 16}{2}, s = \frac{- 2 + L - L ^{2} - 4 L + 16}{2}; L \neq = 0

解答ステップ

L^{- 1} = [\frac{s}{s ^{2} + 2 s - 3}]

改良

\frac{1}{L} = \frac{s}{s ^{2} + 2 s - 3}

たすき掛け

s^{2} + 2 s - 3 = L s; L \neq = 0

解く

s^{2} + 2 s - 3 = L s : s = \frac{- 2 + L + L ^{2} - 4 L + 16}{2}, s = \frac{- 2 + L - L ^{2} - 4 L + 16}{2}

s = \frac{- 2 + L + L ^{2} - 4 L + 16}{2}, s = \frac{- 2 + L - L ^{2} - 4 L + 16}{2}; L \neq = 0