2^{3x+9}=16^{3x+1}

Lösung

2^{3 x + 9} = 1 6^{3 x + 1}

x = \frac{5}{9}

Dezimale

x = 0.55555 \dots

Schritte zur Lösung

2^{3 x + 9} = 1 6^{3 x + 1}

Wende Exponentenregel an

3 x + 9 = 4 (3 x + 1)

Löse

3 x + 9 = 4 (3 x + 1) : x = \frac{5}{9}

x = \frac{5}{9}

\frac{3 ^{10}}{9 ^{x}} = 2 7^{6}

6^{2 x - 4} = 1

4^{x} = 37

4^{x} = 19

3^{a} = \frac{1}{9}