2^{3x}=8^{2x+1}

Lösung

2^{3 x} = 8^{2 x + 1}

x = - 1

Schritte zur Lösung

2^{3 x} = 8^{2 x + 1}

Wende Exponentenregel an

3 x = 3 (2 x + 1)

Löse

3 x = 3 (2 x + 1) : x = - 1

x = - 1

3^{2 x - 3} = \frac{2 7 ^{x + 1}}{2}

e^{- 4 x} - 4 x e^{- 4 x} = 0

1 0^{a} = 92

2 \cdot 5^{x + 1} + 5^{x - 1} = 51

(\frac{1}{2})^{x + 1} = 8