4^x+2^{1+2x}=20

Lösung

4^{x} + 2^{1 + 2 x} = 20

x = \frac{ln ( \frac{20}{3} )}{2 ln ( 2 )}

Dezimale

x = 1.36848 \dots

Schritte zur Lösung

4^{x} + 2^{1 + 2 x} = 20

Wende Exponentenregel an

2 x ln (2) = ln (\frac{20}{3})

Löse

2 x ln (2) = ln (\frac{20}{3}) : x = \frac{ln ( \frac{20}{3} )}{2 ln ( 2 )}

x = \frac{ln ( \frac{20}{3} )}{2 ln ( 2 )}

86400 = 50000 (1 + \frac{1}{5})^{x}

x^{l o g_{3} (x) + 1} = 9

3^{(x - 1)} + 3^{x} = 4

0. 5^{x} = \frac{1}{16}

3^{(x + 2)} = 7