7^{4x+3}=21

Lösung

7^{4 x + 3} = 21

x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

Dezimale

x = - 0.35885 \dots

Schritte zur Lösung

7^{4 x + 3} = 21

Wende Exponentenregel an

(4 x + 3) ln (7) = ln (21)

Löse

(4 x + 3) ln (7) = ln (21) : x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

x = \frac{ln ( \frac{3}{49} )}{4 ln ( 7 )}

(100)^{x} = 1

so l v e f or k, 10.5 = 15 (1 - e^{- 40 k})

\frac{8}{2 ^{n}} = 2

4^{x + 1} = 0.25

450000 = 200000 (1 + 0.12)^{x}