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人気のある代数 >

23305=7000(1+x)^3

解

23305 = 7000 (1 + x)^{3}

解

x = \frac{3 4661}{2 3 175} - 1, x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} + i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}, x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} - i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}

解答ステップ

23305 = 7000 (1 + x)^{3}

辺を交換する

7000 (1 + x)^{3} = 23305

以下で両辺を割る

7000

(1 + x)^{3} = \frac{4661}{1400}

g^{3} (x) = f (a)

の場合, 解は

g (x) = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

解く

1 + x = 3 \frac{4661}{1400} : x = \frac{3 4661}{2 3 175} - 1

解く

1 + x = 3 \frac{4661}{1400} \frac{- 1 + 3 i}{2} : x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} + i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}

解く

1 + x = 3 \frac{4661}{1400} \frac{- 1 - 3 i}{2} : x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} - i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}

解答は

x = \frac{3 4661}{2 3 175} - 1, x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} + i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}, x = \frac{7 ^{\frac{2}{3}} 3 5 ( - 3 4661 - 4 \cdot 5 ^{\frac{2}{3}} 3 7 )}{140} - i \frac{7 ^{\frac{2}{3}} 3 23305 3}{140}

グラフ

人気の例

(6x^2-x-2)(ax+9)=0,a\ne 0

(6 x^{2} - x - 2) (a x + 9) = 0, a \neq = 0

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16 x^{3} + 64 x^{2} - 25 x - 100 = 0

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x^3+3x^2+2x+7=0

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