ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

f^6=sqrt(6+3)

解

f^{6} = 6 + 3

解

f = 33, f = - 33, f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i

解答ステップ

f^{6} = 6 + 3

簡素化

6 + 3 : 3

equationを

u = f^{2}

と以下で書き換える:

u^{3} = f^{6}

u^{3} = 3

解く

u^{3} = 3 : u = 33, u = 33 \frac{- 1 + 3 i}{2}, u = 33 \frac{- 1 - 3 i}{2}

u = 33, u = 33 \frac{- 1 + 3 i}{2}, u = 33 \frac{- 1 - 3 i}{2}

再び

u = f^{2}

に置き換えて以下を解く:

f

解く

f^{2} = 33 : f = 33, f = - 33

解く

f^{2} = 33 \frac{- 1 + 3 i}{2} : f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i

解く

f^{2} = 33 \frac{- 1 - 3 i}{2} : f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i

解答は

f = 33, f = - 33, f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} - \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i, f = - \frac{- 3 3 + 2 3 ^{\frac{2}{3}}}{2} + \frac{3 ^{\frac{5}{6}}}{2 - 3 3 + 2 3 ^{\frac{2}{3}}} i

グラフ

人気の例

x^4-9x^2+11x-2=0

x^{4} - 9 x^{2} + 11 x - 2 = 0

3 x^{3} - x - 2 = 0

b^{3} + 3.31 = 0.41

30x^3+5x^2-25x=0

30 x^{3} + 5 x^{2} - 25 x = 0

solvefor x,V=2x^3-3y^3

so l v e f or x, V = 2 x^{3} - 3 y^{3}