solvefor A,sqrt(BA-h)=t

Lösung

löse nach

A, B A - h = t

A = \frac{t ^{2} + h}{B}

Schritte zur Lösung

B A - h = t

Quadriere beide Seiten:

B A - h = t^{2}

B A - h = t^{2}

Löse

B A - h = t^{2} : A = \frac{t ^{2} + h}{B}

A = \frac{t ^{2} + h}{B}

\frac{1}{2} x - 3 = 0

2 x + 1 + x = 7

2 x + 1 = 3 x - 1

x - 4 = - 2

5 = x^{2} + 9